如何使用 SWIG 将 std::vector<int> 公开为 Python 列表？
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原文地址: http://stackoverflow.com/questions/276769/
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How to expose std::vector<int> as a Python list using SWIG?
提问by Marcos Lara
I'm trying to expose this function to Python using SWIG:
我正在尝试使用 SWIG 将此函数公开给 Python：
std::vector<int> get_match_stats();
And I want SWIG to generate wrapping code for Python so I can see it as a list of integers.
我希望 SWIG 为 Python 生成包装代码，以便我可以将其视为整数列表。
Adding this to the .i file:
将此添加到 .i 文件中：
%include "typemaps.i"
%include "std_vector.i"
namespace std
{
%template(IntVector) vector<int>;
}
I'm running SWIG Version 1.3.36and calling swig with -Walland I get no warnings.
我正在跑步SWIG Version 1.3.36并打电话给 swig-Wall并且我没有收到任何警告。
I'm able to get access to a list but I get a bunch of warnings when compiling with -Wall(with g++ (GCC) 4.2.4) the generated C++ code that say:
我能够访问一个列表，但是在使用-Wall（使用g++ (GCC) 4.2.4）生成的 C++ 代码进行编译时，我收到了一堆警告：
warning: dereferencing type-punned pointer will break strict-aliasing rules
Am I exposing the function correctly? If so, what does the warning mean?
我是否正确公开了该功能？如果是这样，警告是什么意思？
These are the lines before the offending line in the same function:
这些是同一函数中违规行之前的行：
SWIGINTERN PyObject *_wrap_IntVector_erase__SWIG_0(PyObject *SWIGUNUSEDPARM(self), PyObject *args) {
PyObject *resultobj = 0;
std::vector *arg1 = (std::vector *) 0 ;
std::vector::iterator arg2 ;
std::vector::iterator result;
void *argp1 = 0 ;
int res1 = 0 ;
swig::PySwigIterator *iter2 = 0 ;
int res2 ;
PyObject * obj0 = 0 ;
PyObject * obj1 = 0 ;
if (!PyArg_ParseTuple(args,(char *)"OO:IntVector_erase",&obj0,&obj1)) SWIG_fail;
res1 = SWIG_ConvertPtr(obj0, &argp1,SWIGTYPE_p_std__vectorT_int_std__allocatorT_int_t_t, 0 | 0 );
if (!SWIG_IsOK(res1)) {
SWIG_exception_fail(SWIG_ArgError(res1), "in method '" "IntVector_erase" "', argument " "1"" of type '" "std::vector *""'");
}
arg1 = reinterpret_cast * >(argp1);
And this is the offending line:
这是违规行：
res2 = SWIG_ConvertPtr(obj1, SWIG_as_voidptrptr(&iter2), swig::PySwigIterator::descriptor(), 0);
More code follows that.
更多的代码紧随其后。
The warning generated when compiling with g++ 4.2.4 is:
用g++ 4.2.4编译时产生的警告是：
swig_iss_wrap.cxx: In function ‘PyObject* _wrap_IntVector_erase__SWIG_0(PyObject*, PyObject*)': swig_iss_wrap.cxx:5885: warning: dereferencing type-punned pointer will break strict-aliasing rules
采纳答案by Mr Fooz
%template(IntVector) vector<int>;
回答by Fergal
I don't have much experience with Swig, but are you #including your C++ header file in your .i file? Try one (or both) of
我对 Swig 没有太多经验，但是您是否在 .i 文件中#include C++ 头文件？尝试其中一种（或两种）
%include "myvector.h"
%{
# include "myvector.h"
%}
