Shell 脚本：如何从 bash 变量中修剪空格
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Shell Script: How to trim spaces from a bash variable
提问by Bharat Sinha
Possible Duplicate:
How to trim whitespace from bash variable?
可能的重复：
如何从 bash 变量中修剪空格？
I have searched and attempted a number of solutions but nothing seems to work for me...
我已经搜索并尝试了许多解决方案，但似乎没有什么对我有用......
I have a shell variable which is causing issues due to leading and trailing spaces. how can we get rid of all the spaces in a single line using shell script?
我有一个 shell 变量，由于前导和尾随空格而导致问题。我们如何使用shell脚本摆脱一行中的所有空格？
回答by jpmuc
I can think of two options:
我能想到两个选择：
variable=" gfgergj lkjgrg "
echo $variable | sed 's,^ *,,; s, *$,,'
or else
要不然
nospaces=${variable## } # remove leading spaces
nospaces=${variable%% } # remove trailing spaces
回答by Kent
there are so many ways to achieve that, awk oneliner:
有很多方法可以实现这一点，awk oneliner：
kent$ echo " foo - - - bar "|awk '{sub(/^ */,"",##代码##);sub(/ *$/,"",##代码##)}1'
foo - - - bar
