xml 节点名称上的 XPath 通配符
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XPath wildcards on node name
提问by Ben Everard
I want to grab a node from my XML file, the node has a prefix such as "latest_", but this may change and I'm keen for my XSLT to be as fluid as possible. Here's the XPath I want to use:
我想从我的 XML 文件中获取一个节点，该节点有一个前缀，例如“latest_”，但这可能会改变，我希望我的 XSLT 尽可能流畅。这是我要使用的 XPath：
/data/stats/*_cost
This should match latest_cost, newest_cost, anything_cost, is there a way of doing this?
这应该匹配latest_cost, newest_cost, anything_cost，有没有办法做到这一点？
Cheers :-)
干杯:-)
回答by
This is the correct XPath 1.0 expression which selects an element with the last 5 character of name equal to "_cost" in any namespace.
这是正确的 XPath 1.0 表达式，它在任何命名空间中选择名称的最后 5 个字符等于“_cost”的元素。
/data/stats/*[substring(name(), string-length(name()) - 4) = '_cost']
回答by redsquare
You could also use contains
你也可以使用 contains
e.g
例如
/data/stats[contains(.,'_cost')]
回答by Alex Nikolaenkov
With XPath 1.0 you can use /data/stats/*[substring-after(name(), '_cost') = '']pattern. That checks if the element's name ends with the _costsuffix.
在 XPath 1.0 中，您可以使用/data/stats/*[substring-after(name(), '_cost') = '']模式。这将检查元素的名称是否以_cost后缀结尾。
In XPath 2.0 there is fn:ends-with(str, str)and your corresponding expression will be *[ends-with(name(), '_cost')].
在 XPath 2.0 中fn:ends-with(str, str)，您的相应表达式将是*[ends-with(name(), '_cost')].
回答by David W.
The above did not work for me. I had to "slightly" modify that as follows:
以上对我不起作用。我不得不“稍微”修改如下：
/data/stats/*[contains(name(),'_cost')]
