java 在 servlet 中获取请求 url 的一部分

Getting part of request url inside servlet

提问by JAVAGeek

I have an EmailVerificationServlet mapped with /ev/*url-pattern.

我有一个EmailVerification用/ev/*url-pattern映射的Servlet 。

http://example.com/ev/ce52320570

How can I get this ce52320570part of the URL in my Servlet?

如何ce52320570在我的 Servlet 中获取URL 的这一部分？

protected void doPost(HttpServletRequest request, HttpServletResponse response)
                                                     throws ServletException, IOException {
      String vid = "";  // Here I need to get the id from the URL
}

回答by acdcjunior

Considering a Servlet (called EmailVerification) mapped to /ev/*:

考虑EmailVerification映射到的 Servlet（称为）/ev/*：

Will the URL http://example.com/ev/ce52320570trigger the EmailVerificationservlet ?

URL 会http://example.com/ev/ce52320570触发EmailVerificationservlet 吗？

Yes. In Servlet versions 2.5 and 3.0 (maybe earlier), it'll get the subpath if you map it with *, like /ev/*, as you did.

是的。在 Servlet 版本 2.5 和 3.0（可能更早）中，如果您*像 一样使用映射它，它将获得子路径/ev/*。

How can I get this ce52320570part of the URL http://example.com/ev/ce52320570?

如何获取ce52320570URL 的这一部分http://example.com/ev/ce52320570？

• request.getRequestURI()will get you the requested URL as a String, like /ev/ce52320570.

• request.getPathInfo()gets you (if exists) everything after /ev/.

  • So in a request to /ev/123, getPathInfo()would give you /123. The same way, a request to /ev/some/other, getPathInfo()would give you /some/other.

• request.getQueryString()should be used if you need the query parameterspart of the URL.

  • Keep in mind both getRequestURI()and getPathInfo()give you only the pathrequested. If you need to obtain the query parameters, that is, those after the ?, like /ev/something?query1=value1&other=123, only request.getQueryString()would return the query1=value1&other=123part.

• request.getParameter(parameterName)if you need the value of a specificquery parameter.

  • Resort to .getParameterValues()if it is a multivalued parameter

• request.getRequestURI()将为您提供请求的 URL String，例如/ev/ce52320570.

• request.getPathInfo()让你（如果存在）之后的一切/ev/。

  • 所以在一个请求中/ev/123，getPathInfo()会给你/123。用同样的方法，一个请求/ev/some/other，getPathInfo()会给你/some/other。

• request.getQueryString()如果您需要URL的查询参数部分，则应该使用它。

  • 记住两者getRequestURI()，只getPathInfo()给你请求的路径。如果需要获取查询参数，即?, like之后的/ev/something?query1=value1&other=123，只request.getQueryString()返回query1=value1&other=123部分。

• request.getParameter(parameterName)如果您需要特定查询参数的值。

  • 再打.getParameterValues()，如果它是一个多值参数

---

---

More examples of the URL parts in the request here.

此处请求中的 URL 部分的更多示例。

回答by Mateusz

Use request.getRequestURI()and remove what you don't need, i.e. request.getRequestURI().replace("/ev/");

使用request.getRequestURI()并删除您不需要的东西，即request.getRequestURI().replace("/ev/");