java 在java中将String / char转换为指定数字的二进制字符串，反之亦然
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Convert String / char into specified-digit binary string and vice versa in java
提问by tugcem
I'm trying to convert a string (or a single char) into given number of digits binary string in java. Assume that given number is 5, so a string "zx~q" becomes 01101, 10110, 11011, 10011 (I' ve made up the binaries). However, I need to revert these binaries into "abcd" again. If given number changes, the digits (so the binaries) will change.
我正在尝试在 java 中将字符串（或单个字符）转换为给定位数的二进制字符串。假设给定的数字是 5，那么字符串“zx~q”就变成了 01101、10110、11011、10011（我已经编好了二进制文件）。但是，我需要再次将这些二进制文件恢复为“abcd”。如果给定的数字发生变化，数字（二进制）也会发生变化。
Anyone has an idea?
有人有想法吗？
PS: Integer.toBinaryString()changes into an 8-digit binary array.
PS：Integer.toBinaryString()变成8位二进制数组。
回答by SirPentor
Looks like Integer.toString(int i, int radix)and Integer.parseInt(string s, int radix)would do the trick.
看起来Integer.toString(int i, int radix)并且Integer.parseInt(string s, int radix)会做到这一点。
回答by Ajay S
You can achieve like this.
你可以这样实现。
To convert abcdto 1010101111001101,
要将abcd转换为 1010101111001101，
class Demo {
public static void main(String args[]) {
String str = "abcd";
for(int i = 0; i < str.length(); i++) {
int number = Integer.parseInt(String.valueOf(str.charAt(i)), 16);
String binary = Integer.toBinaryString(number);
System.out.print(binary);
}
}
}
To convert the 1010101111001101 to abcd
将 1010101111001101 转换为 abcd
String str = "1010101111001101";
String binary = Long.toHexString(Long.parseLong(str,2));
System.out.print(binary);
