如何在Python中获得timedelta的总和？
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How to get the sum of timedelta in Python?
提问by user469652
Python: How to get the sum of timedelta?
Python：如何获得timedelta的总和？
Eg. I just got a lot of timedelta object, and now I want the sum. That's it!
例如。我刚刚得到了很多 timedelta 对象，现在我想要总和。就是这样！
采纳答案by pyfunc
datetime combine method allows you to combine time with a delta
日期时间组合方法允许您将时间与增量组合
datetime.combine(date.today(), time()) + timedelta(hours=2)
timedelta can be combined using usual '+' operator
timedelta 可以使用通常的“+”运算符组合
>>> timedelta(hours=3)
datetime.timedelta(0, 10800)
>>> timedelta(hours=2)
datetime.timedelta(0, 7200)
>>>
>>> timedelta(hours=3) + timedelta(hours=2)
datetime.timedelta(0, 18000)
>>>
You can read the datetime module docs and a very good simple introduction at
您可以阅读 datetime 模块文档和一个非常好的简单介绍
回答by Mark Byers
To add timedeltas you can use the builtin operator +:
要添加 timedeltas，您可以使用内置运算符+：
result = timedelta1 + timedelta2
To add a lot of timedeltas you can use sum:
要添加大量时间增量，您可以使用 sum：
result = sum(timedeltas, datetime.timedelta())
Or reduce:
或减少：
import operator
result = reduce(operator.add, timedeltas)
回答by af.
As this "just works", I assume this question lacks some detail...
由于这“有效”，我认为这个问题缺乏一些细节......
Just like this:
像这样：
>>> import datetime
>>> datetime.timedelta(seconds=10) + datetime.timedelta(hours=5)
datetime.timedelta(0, 18010)
回答by Doug F
I am pretty sure that by "sum" he means that he wants the value of the sum in a primitive type (eg integer) rather than a datetime object.
我很确定“总和”的意思是他想要原始类型（例如整数）而不是日期时间对象的总和值。
Note that you can always use the dirfunction to reflect on an object, returning a list of its methods and attributes.
请注意，您始终可以使用该dir函数来反映对象，返回其方法和属性的列表。
>>> import datetime
>>> time_sum=datetime.timedelta(seconds=10) + datetime.timedelta(hours=5)
>>> time_sum
datetime.timedelta(0, 18010)
>>> dir(time_sum)
['__abs__', '__add__', '__class__', '__delattr__', '__div__', '__doc__', '__eq__', '__floordiv__', '__ge__', '__getattribute__', '__gt__', '__hash__', '__init__', '__le__', '__lt__', '__mul__', '__ne__', '__neg__', '__new__', '__nonzero__', '__pos__', '__radd__', '__rdiv__', '__reduce__', '__reduce_ex__', '__repr__', '__rfloordiv__', '__rmul__', '__rsub__', '__setattr__', '__str__', '__sub__', 'days', 'max', 'microseconds', 'min', 'resolution', 'seconds']
So in this case, it looks like we probably want seconds.
所以在这种情况下，看起来我们可能需要几秒钟。
>>> time_sum.seconds
18010
Which looks right to me:
这对我来说是正确的：
>>> 5*60*60 + 10
18010
回答by RobM
(Edit:Assuming that by "sum timedelta" you mean "convert a timedelta to int seconds".)
（编辑：假设“sum timedelta”是指“将 timedelta 转换为 int 秒”。）
This is very inefficient, but it is simple:
这是非常低效的，但很简单：
int((datetime.datetime.fromtimestamp(0) + myTimeDelta).strftime("%s"))
This converts a Unix timestamp (0) into a datetime object, adds your delta to it, and then converts back to a Unix time. Since Unix time counts seconds, this is the number of seconds your timedelta represented.
这会将 Unix 时间戳 ( 0) 转换为日期时间对象，将您的增量添加到其中，然后转换回 Unix 时间。由于 Unix 时间计算秒数，这是您的 timedelta 表示的秒数。
