Python 检查另一个字符串中是否存在多个字符串
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/3389574/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Check if multiple strings exist in another string
提问by jahmax
How can I check if any of the strings in an array exists in another string?
如何检查数组中的任何字符串是否存在于另一个字符串中？
Like:
喜欢：
a = ['a', 'b', 'c']
str = "a123"
if a in str:
print "some of the strings found in str"
else:
print "no strings found in str"
That code doesn't work, it's just to show what I want to achieve.
该代码不起作用，只是为了显示我想要实现的目标。
采纳答案by Mark Byers
回答by Seamus Campbell
You need to iterate on the elements of a.
您需要迭代 a 的元素。
a = ['a', 'b', 'c']
str = "a123"
found_a_string = False
for item in a:
if item in str:
found_a_string = True
if found_a_string:
print "found a match"
else:
print "no match found"
回答by mluebke
a = ['a', 'b', 'c']
str = "a123"
a_match = [True for match in a if match in str]
if True in a_match:
print "some of the strings found in str"
else:
print "no strings found in str"
回答by jbernadas
You should be careful if the strings in aor strgets longer. The straightforward solutions take O(S*(A^2)), where Sis the length of strand A is the sum of the lenghts of all strings in a. For a faster solution, look at Aho-Corasickalgorithm for string matching, which runs in linear time O(S+A).
如果字符串变长a或str变长，您应该小心。简单的解决方案采用 O(S*(A^2))，其中S是 的长度，strA 是 中所有字符串的长度之和a。要获得更快的解决方案，请查看用于字符串匹配的Aho-Corasick算法，该算法在线性时间 O(S+A) 内运行。
回答by Shankar ARUL - jupyterdata.com
Just to add some diversity with regex:
只是为了增加一些多样性regex：
import re
if any(re.findall(r'a|b|c', str, re.IGNORECASE)):
print 'possible matches thanks to regex'
else:
print 'no matches'
or if your list is too long - any(re.findall(r'|'.join(a), str, re.IGNORECASE))
或者如果你的清单太长—— any(re.findall(r'|'.join(a), str, re.IGNORECASE))
回答by zondo
any()is by far the best approach if all you want is Trueor False, but if you want to know specifically which string/strings match, you can use a couple things.
any()如果您想要的只是Trueor False，这是迄今为止最好的方法，但是如果您想具体知道哪个字符串/字符串匹配，您可以使用一些东西。
If you want the first match (with Falseas a default):
如果你想要第一场比赛（False默认情况下）：
match = next((x for x in a if x in str), False)
If you want to get all matches (including duplicates):
如果要获取所有匹配项（包括重复项）：
matches = [x for x in a if x in str]
If you want to get all non-duplicate matches (disregarding order):
如果您想获得所有非重复匹配项（不考虑顺序）：
matches = {x for x in a if x in str}
If you want to get all non-duplicate matches in the right order:
如果您想以正确的顺序获取所有非重复匹配项：
matches = []
for x in a:
if x in str and x not in matches:
matches.append(x)
回答by Trinadh Koya
It depends on the context suppose if you want to check single literal like(any single word a,e,w,..etc) inis enough
这取决于上下文猜，如果你要检查，如单文字（任何一个字，E，W，..等）在足够
original_word ="hackerearcth"
for 'h' in original_word:
print("YES")
if you want to check any of the character among the original_word: make use of
如果要检查 original_word 中的任何字符：请使用
if any(your_required in yourinput for your_required in original_word ):
if you want all the input you want in that original_word,make use of all simple
如果你想在那个 original_word 中输入你想要的所有输入，请使用 all simple
original_word = ['h', 'a', 'c', 'k', 'e', 'r', 'e', 'a', 'r', 't', 'h']
yourinput = str(input()).lower()
if all(requested_word in yourinput for requested_word in original_word):
print("yes")
回答by Domi W
jbernadas already mentioned the Aho-Corasick-Algorithmin order to reduce complexity.
jbernadas 已经提到了Aho-Corasick-Algorithm以降低复杂性。
Here is one way to use it in Python:
这是在 Python 中使用它的一种方法：
Download aho_corasick.py from here
Put it in the same directory as your main Python file and name it
aho_corasick.pyTry the alrorithm with the following code:
from aho_corasick import aho_corasick #(string, keywords) print(aho_corasick(string, ["keyword1", "keyword2"]))
从这里下载 aho_corasick.py
将它放在与主 Python 文件相同的目录中并命名
aho_corasick.py使用以下代码尝试算法：
from aho_corasick import aho_corasick #(string, keywords) print(aho_corasick(string, ["keyword1", "keyword2"]))
Note that the search is case-sensitive
注意搜索区分大小写
回答by LeftSpace
flog = open('test.txt', 'r')
flogLines = flog.readlines()
strlist = ['SUCCESS', 'Done','SUCCESSFUL']
res = False
for line in flogLines:
for fstr in strlist:
if line.find(fstr) != -1:
print('found')
res = True
if res:
print('res true')
else:
print('res false')
回答by Ivan Mikhailov
I would use this kind of function for speed:
我会使用这种功能来提高速度：
def check_string(string, substring_list):
for substring in substring_list:
if substring in string:
return True
return False
