laravel php中字符串到数组的转换
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String to array conversion in php
提问by Kayal
I got the string from the ajax and passed the string in url as 1,2,3,4,5,6
我从 ajax 中获取字符串，并将 url 中的字符串作为 1,2,3,4,5,6 传递
After using explode function,
i.e. $explode_id = explode(',', $request->data);I got the output as
["1","2","3","4","5","6"]
使用爆炸功能后，即$explode_id = explode(',', $request->data);我得到的输出为 ["1","2","3","4","5","6"]
But I want the data as: [1,2,3,4,5,6]
但我希望数据为：[1,2,3,4,5,6]
How do I get it? And it should not be like ["1,2,3,4,5,6"] Because I want to compare the data in:
我如何得到它？它不应该像 ["1,2,3,4,5,6"] 因为我想比较以下数据：
$product_id = Product::where('name', 'like','%'.$main.'%')->where('id', $explode_id)->pluck('id');
I got the answer here. Am passing the id that i want to match in URL like
我在这里得到了答案。正在传递我想在 URL 中匹配的 ID，例如
$("input[type='checkbox']").click(function() {
if ($(this).is(':checked')) {
var days = $(this).val();
$.ajax({
type: "get",
url: '/getcreatedat',
data: { 'days': days },
success: successFunc,
error: errorFunc
});
function successFunc(data, status) {
var pageURL = $(location).attr("href");
window.location.href = pageURL+ '/' +data;
}
function errorFunc(xhr, error) {
console.log(error);
}
}
});
The next time I click the function: url passing the id's double the time
下次我点击函数时：url 传递 id 的时间是两倍
回答by Vishal Solanki
@Kayal try it with array_map() with inval like below:
@Kayal 尝试使用带有 inval 的 array_map()，如下所示：
<?php
$explode_id = array_map('intval', explode(',', $request->data));
回答by Neat
You can just json_decodeit.
你就可以json_decode了。
$explode_id = json_decode($request->data, true);
Also, if you're trying to do a IN()condition, you can use:
此外，如果您尝试执行IN()条件，则可以使用：
->whereIn('id', $explode_id);
回答by Red Bottle
I'd do it this way, try this...
我会这样做，试试这个...
$a = "1,2,3,4,5";
$b= preg_split("/[,]/",$a);
print_r($b);
回答by Shyamali
You can use str_replace('"','',$string[$i]);inside a for loop for each array element or else you can do it as
您可以str_replace('"','',$string[$i]);在 for 循环内为每个数组元素使用，否则您可以这样做
$intVal = (int)$string[$i];
in side a for loop
在 for 循环侧
