vb.net 检查一个数字是否可以被另一个数字整除的快速方法？
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Fast way to check if a number is evenly divisible by another?
提问by pimvdb
I was wondering what the fastest way is to check for divisibility in VB.NET.
我想知道在 VB.NET 中检查可分性的最快方法是什么。
I tried the following two functions, but I feel as if there are more efficient techniques.
我尝试了以下两个功能，但感觉好像有更高效的技巧。
Function isDivisible(x As Integer, d As Integer) As Boolean
Return Math.floor(x / d) = x / d
End Function
Another one I came up with:
我想出了另一个：
Function isDivisible(x As Integer, d As Integer) As Boolean
Dim v = x / d
Dim w As Integer = v
Return v = w
End Function
Is this a more practical way?
这是更实用的方法吗？
回答by gor
Use Mod:
使用Mod：
Function isDivisible(x As Integer, d As Integer) As Boolean
Return (x Mod d) = 0
End Function
回答by Matt F
Use 'Mod' which returns the remainder of number1 divided by number2. So if remainder is zero then number1 is divisible by number2.
使用 'Mod' 返回 number1 除以 number2 的余数。因此，如果余数为零，则 number1 可被 number2 整除。
e.g.
例如
Dim result As Integer = 10 Mod 5 ' result = 0
Dim 结果为整数 = 10 Mod 5 ' 结果 = 0
回答by kefeizhou
use the mod operator
使用mod 运算符
