java java中的%运算符是什么？
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What is the % operator in java?
提问by LipstickQueen
public static int sumDigits (int n) {
if(n < 10)
return n;
else
return n%10 + sumDigits (n/10);
}
This method is used to calculate the sum of the digits in a number recursively, but I do not understand it? What is the purpose of n%10???
这个方法是用来递归计算一个数的各位数之和的，但是我不明白？n%10 的目的是什么？？？
回答by Eran
n%10gives you the least significant digit of nby calculating the remainder of dividing the number by 10.
n%10n通过计算将数字除以 10 的余数，为您提供 的最低有效位。
Hence, the method returns the sum of the least significant digit and the sum of digits of n/10(which is the number that contains all the digits of nexcept of the least significant digit).
因此，该方法返回最低有效数字的总和和 的数字总和n/10（即包含n除最低有效数字之外的所有数字的数字）。
回答by Raman Sahasi
n%10means modulus of 10. This is used to get last digit.
n%10表示 的模数10。这用于获取最后一位数字。
Let's say your number is 12345
假设你的号码是 12345
12345 % 10means remainder when 12345is divided by 10, which gives you 5.
12345 % 10表示12345除以时的余数10，得到5。
Thereafter when you perform (n/10)you get 1234(all the numbers except the least significant digit that you got in previous step).
此后，当您执行时，您(n/10)将获得1234（除上一步中获得的最低有效数字之外的所有数字）。
回答by SPlatten
% is modulus, so n mod 10, it returns the remainder after n / 10.
% 是模数，所以 n mod 10，它返回 n / 10 之后的余数。
if n is 1 to 10, then it will return 1 to 9 and 0 when n is 10.
如果 n 是 1 到 10，那么当 n 是 10 时，它将返回 1 到 9 和 0。
回答by Stuti Rastogi
n%10means the modulus of 10, that is the remainder you get when you divide with 10. Here it is used to get each digit.
n%10表示10的模数，也就是你除以10得到的余数。这里用来得到每个数字。
Example:
例子：
Say your number is n = 752.
假设您的数字是 n = 752。
n%10 = 2, n/10 = 75
n%10 = 2, n/10 = 75
So you add 2 to the sumDigits(75)
所以你把 2 添加到 sumDigits(75)
Now, n%10 = 75%10 = 5. This is the digit to be added and so on, till your n >= 10. When it is < 10, you have a single digit that you just need to return as it is, as that is only the sum of digits in that single-digit number n.
现在，n%10 = 75%10 = 5。这是要添加的数字，依此类推，直到您的n >= 10. 当它是 时< 10，您只需要按原样返回一位数字，因为这只是该一位数字 n 中的数字之和。
