Bash：管道查找到 Grep
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Bash : Piping Find into Grep
提问by user2135970
The following command finds all occurrences of 'some string' by recursively searching through the current directory and all sub-directories
以下命令通过递归搜索当前目录和所有子目录来查找所有出现的“某个字符串”
grep -r -n 'some string' .
This command recursively searches through current directory and all sub-directories and returns all files of the form *.axvw
此命令递归搜索当前目录和所有子目录并返回 *.axvw 形式的所有文件
find . -name '*.axvw'
I want to put these two commands together so I get all occurances of 'some string' by recursively searching through the current directory but only looking at files that end in 'axvw'.
我想将这两个命令放在一起，以便通过递归搜索当前目录但只查看以“axvw”结尾的文件来获取所有出现的“某个字符串”。
When I tried running the following command nothing was returned:
当我尝试运行以下命令时，没有返回任何内容：
find . -name '*js' | grep -n 'some string'
What am I doing wrong?
我究竟做错了什么？
回答by anubhava
You can use -execoption in find:
您可以-exec在find以下选项中使用选项：
find . -name '*.axvw' -exec grep -n 'some string' {} +
Or else use xargs:
否则使用xargs：
find . -name '*.axvw' -print0 | xargs -0 grep -n 'some string'
回答by sjwarner
find . -name '*js' -exec grep -n 'some string' {} \;
find . -name '*js' -exec grep -n 'some string' {} \;
Should work I think.
我认为应该工作。
Edit: just for fun, you could also use a double grep I believe.
编辑：只是为了好玩，我相信你也可以使用双 grep。
find . | grep 'some string' | grep js
find . | grep 'some string' | grep js
