Javascript 如何在php代码中调用javascript函数？
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How to call javascript function in php code?
提问by Kalpana Dixit
on my login form, i am putting server side validations and if error occurs i want to display those error just below the validated control. Now for this, i am trying to call javascript function to show validation message in php code but not able to call.
在我的登录表单上，我将进行服务器端验证，如果发生错误，我想在经过验证的控件下方显示这些错误。现在为此，我正在尝试调用 javascript 函数以在 php 代码中显示验证消息，但无法调用。
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST')
{
if($_POST['txtUsername']=='')
{
//here i want to call javascript function to display message
}
}
?>
<form action="login.php" method="POST">
Username <input type="text" size="30" name="txtUsername" id="user" /><br />
Password <input type="password" size="30" name="txtPassword" id="pass" /><br />
<input type="submit" value="Login" name="loginSubmit"/>
</form>
<script type="text/javascript">
function showMessage(value)
{
document.getElementById(value).innerHTML= value+"can not be empty.";
}
</script>
Please tell me how to display server side validation just below the validated control in form.
请告诉我如何在表单中经过验证的控件下方显示服务器端验证。
回答by Aamir Mahmood
Something like this
像这样的东西
<html>
<head>
<script type="text/javascript">
function showMessage(value)
{
document.getElementById(value).innerHTML= value+"can not be empty.";
}
</script>
</head>
<body>
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST')
{
if($_POST['txtUsername']=='')
{
echo '<script> showMessage("txtUsername"); </script>';
}
}
?>
<form action="login.php" method="POST">
Username <input type="text" size="30" name="txtUsername" id="txtUsername" /><br />
Password <input type="password" size="30" name="txtPassword" id="txtPassword" /><br />
<input type="submit" value="Login" name="loginSubmit"/>
</form>
</body>
</html>
回答by Yogesh Suthar
use this
用这个
if($_POST['txtUsername']=='')
{
echo '<script> showMessage("txtUsername"); </script>';
}
回答by Riste
You can put your php code anywhere you like let's say in the body like attribute. You can try the following code:
你可以把你的 php 代码放在任何你喜欢的地方，比如在 body like 属性中。您可以尝试以下代码：
<body <?php
if($_SERVER['REQUEST_METHOD'] == 'POST')
{
if($_POST['txtUsername']=='')
{
echo "onload = 'showMessage("VALUE")'";
}
}
?> > // end of body start tag
<form action="login.php" method="POST">
Username <input type="text" size="30" name="txtUsername" id="user" /><br />
Password <input type="password" size="30" name="txtPassword" id="pass" /><br />
<input type="submit" value="Login" name="loginSubmit"/>
</form>
</body>
<script type="text/javascript">
function showMessage(value)
{
document.getElementById(value).innerHTML= value+"can not be empty.";
}
</script>
If the validation is successful the php code wont echo anything and the javascript function will not be called. Works for me :). Tell me if this helps.
如果验证成功，php 代码不会回显任何内容，并且不会调用 javascript 函数。对我有用:)。告诉我这是否有帮助。
回答by Samy
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST')
{
if($_POST['txtUsername']=='')
{
?>
<script>
//Define the function somewhere in the top or in external js and include it.
callyourfunction();
</script>
<?php
}
}
?> //Its not working
