java 加载多个 YAML 文件(使用 @ConfigurationProperties?)
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Loading multiple YAML files (using @ConfigurationProperties?)
提问by Alex
Using Spring Boot 1.3.0.RELEASE
使用 Spring Boot 1.3.0.RELEASE
I have a couple of yaml files that describe several instances of a program. I now want to parse all those files into a List<Program>
(Map, whatever), so I can later on search for the most appropriate instance for a given criteria in all the programs.
我有几个 yaml 文件描述了一个程序的几个实例。我现在想将所有这些文件解析成一个List<Program>
(地图,无论如何),这样我以后就可以在所有程序中为给定条件搜索最合适的实例。
I like the approach with @ConfigurationProperties
a lot, and it works good enough for a single yaml-file, but I haven't found a way yet to read all files in a directory using that method.
我很喜欢这种方法@ConfigurationProperties
,它对于单个 yaml 文件来说已经足够好了,但是我还没有找到一种方法来使用该方法读取目录中的所有文件。
Current approach working for a single file:
当前适用于单个文件的方法:
programs/program1.yml
name: Program 1
minDays: 4
maxDays: 6
can be read by
可以阅读
@Configuration
@ConfigurationProperties(locations = "classpath:programs/program1.yml", ignoreUnknownFields = false)
public class ProgramProperties {
private Program test; //Program is a POJO with all the fields in the yml.
//getters+setters
I tried changing the locations to an Array listing all of my files locations = {"classpath:programs/program1.yml", "classpath:programs/program2.yml"}
as well as using locations = "classpath:programs/*.yml"
, but that still only loads the first file (array-approach) or nothing at all (wildcard-approach).
我尝试将位置更改为列出我所有文件的数组locations = {"classpath:programs/program1.yml", "classpath:programs/program2.yml"}
以及使用locations = "classpath:programs/*.yml"
,但这仍然只加载第一个文件(数组方法)或根本不加载(通配符方法)。
So, my question is, what is the best way in Spring Boot to load a bunch of yaml files in a classpath-directory and parse them into a (List of) POJO, so they can be autowired in a Controller? Do I need to use Snakeyaml directly, or is there an integrated mechanism that I just haven't found yet?
所以,我的问题是,Spring Boot 中在类路径目录中加载一堆 yaml 文件并将它们解析为(列表)POJO,以便它们可以在控制器中自动装配的最佳方法是什么?我是否需要直接使用 Snakeyaml,或者是否有我还没有找到的集成机制?
EDIT: A working approach is doing it manually:
编辑:一种工作方法是手动进行:
private static final Yaml yaml = new Yaml(new Constructor(Program.class));
private static final ResourcePatternResolver resolver = new PathMatchingResourcePatternResolver();
try {
for (Resource resource : resolver.getResources("/programs/*.yml")) {
Object data = yaml.load(resource.getInputStream());
programList.add((Program) data);
}
}
catch (IOException ioe) {
logger.error("failed to load resource", ioe);
}
回答by mchlfchr
What I am currently doing, as far as I understood your question, is nearly the same.
I am having an application.yml
and also profile-specific yml files, e.g. application-{profile}.yml
in my src/main/resources
.
In the application.yml
I have defined the default profile key-values, which are partially overridden by the profile-specific yml files.
据我了解您的问题,我目前正在做的事情几乎相同。我有一个application.yml
特定application-{profile}.yml
于配置文件的 yml 文件,例如在我的src/main/resources
. 在application.yml
我定义了默认的配置文件键值,这些键值被特定于配置文件的 yml 文件部分覆盖。
If you want to have a type-safe and well defined access of your YML key/values, then you can use the following approach:
如果您想对 YML 键/值进行类型安全且定义明确的访问,则可以使用以下方法:
@ConfigurationProperties
public class AppSettings {
String name; // has to be the same as the key in your yml file
// setters/getters
}
In your Spring-Boot config, you have to add the following annotations onto your config class:
在您的 Spring-Boot 配置中,您必须将以下注释添加到您的配置类中:
@ComponentScan
@EnableAutoConfiguration
@EnableConfigurationProperties( value = { AppSettings.class, SomeOtherSettings.class } )
public class SpringContextConfig {
@Autowired
private AppSettings appSettings;
public void test() {
System.out.println(appSettings.getName());
}
}
The @Autowiring
is also accessible from other Beans.
The other way around (without an extra separated and type-safe class, is to access the YML-values via @Value("${name}")
.
该@Autowiring
也与其他豆类访问。另一种方法(没有额外的分离和类型安全的类,是通过@Value("${name}")
.
To bring it together in a short manner:
Yes, it is possible to use several YAML files for your application via Spring-profiles. You define your current active spring profile via command args, programmatically or via your system env (SPRING_PROFILES_ACTIVE=name1,name2).
Therefore you can have several application.yml
files for each profile (see above).
简而言之:是的,可以通过 Spring-profiles 为您的应用程序使用多个 YAML 文件。您可以通过命令 args、以编程方式或通过系统环境 (SPRING_PROFILES_ACTIVE=name1,name2) 定义当前活动的 spring 配置文件。因此,您可以application.yml
为每个配置文件创建多个文件(见上文)。
回答by Mohit
In Spring, it is possible to load multiple configuration properties files using PropertySource
annotation, but not YAML files. See section 26.6.4 in link below:
在 Spring 中,可以使用PropertySource
注释加载多个配置属性文件,但不能使用 YAML 文件。请参阅以下链接中的第 26.6.4 节:
However, from your problem, it seems that you can configure all your programs in single YAML and then get all list of programs in a single list.
但是,从您的问题来看,您似乎可以在单个 YAML 中配置所有程序,然后在单个列表中获取所有程序列表。
Sample YAML (all.yaml)
示例 YAML (all.yaml)
programs:
- name: A
min: 1
max: 2
- name: B
min: 3
max: 4
Config.java
配置文件
@Configuration
@ConfigurationProperties(locations={"classpath:all.yaml"})
public class Config{
private List<Program> programs;
public void setPrograms(List<Program> programs) {
this.programs = programs;
}
public List<Program> getPrograms() {
return programs;
}
}