动态资源加载Android
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Dynamic Resource Loading Android
提问by Jason Rogers
I'm trying to find a way to open resources whose name is determined at runtime only.
我试图找到一种方法来打开其名称仅在运行时确定的资源。
More specifically, I want to have a XML that references a bunch of other XML files in the application apk. For the purpose of explaining, let's say the main XML is main.xmland the other XML are file1.xml, file2.xmland fileX.xml. What I want is to read main.xml, extract the name of the XML I want (fileX.xml), for example, and then read fileX.xml. The problem I face is that what I extract form main.xmlis a string and I can't find a way to change that to R.raw.nameOfTheFile.
更具体地说，我想要一个 XML 引用应用程序 apk 中的一堆其他 XML 文件。为了解释的目的，假设主要的 XML 是main.xml，其他的 XML 是file1.xml,file2.xml和fileX.xml。我想要的是读取main.xml，例如提取我想要的 XML 的名称 ( fileX.xml)，然后读取fileX.xml. 我面临的问题是我提取的表单main.xml是一个字符串，我找不到将其更改为R.raw.nameOfTheFile.
Anybody has an idea?
有人有想法吗？
I don't want to:
我不想：
- regroup everything in one huge XML file
- hardcode main.xml in a huge switch case that links a number/string to the resource ID
- 将所有内容重新组合到一个巨大的 XML 文件中
- 在一个巨大的 switch case 中硬编码 main.xml，将数字/字符串链接到资源 ID
回答by Mathias Conradt
I haven't used it with raw files or xml layout files, but for drawables I use this:
我没有将它与原始文件或 xml 布局文件一起使用，但对于可绘制文件，我使用了这个：
getResources().getIdentifier("fileX", "drawable","com.yourapppackage.www");
to get the identifier (R.id) of the resource. You would need to replace drawable with something else, maybe rawor layout(untested).
获取资源的标识符 (R.id)。您可能需要用其他东西替换 drawable，也许raw或layout（未经测试）。
回答by E-Riz
I wrote this handy little helper method to encapsulate this:
我写了这个方便的小助手方法来封装它：
public static String getResourceString(String name, Context context) {
int nameResourceID = context.getResources().getIdentifier(name, "string", context.getApplicationInfo().packageName);
if (nameResourceID == 0) {
throw new IllegalArgumentException("No resource string found with name " + name);
} else {
return context.getString(nameResourceID);
}
}
