Java - 将 int 转换为 4 字节的字节数组？
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Java - Convert int to Byte Array of 4 Bytes?
提问by Petey B
Possible Duplicate:
Convert integer into byte array (Java)
可能的重复：
将整数转换为字节数组（Java）
I need to store the length of a buffer, in a byte array 4 bytes large.
我需要将缓冲区的长度存储在一个 4 字节大的字节数组中。
Pseudo code:
伪代码：
private byte[] convertLengthToByte(byte[] myBuffer)
{
int length = myBuffer.length;
byte[] byteLength = new byte[4];
//here is where I need to convert the int length to a byte array
byteLength = length.toByteArray;
return byteLength;
}
What would be the best way of accomplishing this? Keeping in mind I must convert that byte array back to an integer later.
实现这一目标的最佳方法是什么？请记住，我必须稍后将该字节数组转换回整数。
采纳答案by Waldheinz
You can convert yourIntto bytes by using a ByteBufferlike this:
您可以yourInt使用ByteBuffer这样的方式转换为字节：
return ByteBuffer.allocate(4).putInt(yourInt).array();
Beware that you might have to think about the byte orderwhen doing so.
请注意，这样做时您可能必须考虑字节顺序。
回答by Sorrow
This should work:
这应该有效：
public static final byte[] intToByteArray(int value) {
return new byte[] {
(byte)(value >>> 24),
(byte)(value >>> 16),
(byte)(value >>> 8),
(byte)value};
}
Code taken from here.
代码取自此处。
EditAn even simpler solution is given in this thread.
编辑此线程中给出了更简单的解决方案。
回答by Stas Jaro
int integer = 60;
byte[] bytes = new byte[4];
for (int i = 0; i < 4; i++) {
bytes[i] = (byte)(integer >>> (i * 8));
}
回答by Hari Perev
public static byte[] my_int_to_bb_le(int myInteger){
return ByteBuffer.allocate(4).order(ByteOrder.LITTLE_ENDIAN).putInt(myInteger).array();
}
public static int my_bb_to_int_le(byte [] byteBarray){
return ByteBuffer.wrap(byteBarray).order(ByteOrder.LITTLE_ENDIAN).getInt();
}
public static byte[] my_int_to_bb_be(int myInteger){
return ByteBuffer.allocate(4).order(ByteOrder.BIG_ENDIAN).putInt(myInteger).array();
}
public static int my_bb_to_int_be(byte [] byteBarray){
return ByteBuffer.wrap(byteBarray).order(ByteOrder.BIG_ENDIAN).getInt();
}
