如何使用 PHP 在 HTML 中创建表格
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How to create a table in HTML using PHP
提问by Eli Skywalker
I have 5 pictures stored in a folder and their links stored on the database. I want to put them in a table of three columns on each row.
我有 5 张图片存储在一个文件夹中，它们的链接存储在数据库中。我想将它们放在每行三列的表格中。
<body>
<center>
<table border='1'>
<?php
$host="";
$username="";
$password="";
$db_name="fruits_db";
$tbl_name="fruits_tbl";
$connection=mysqli_connect("$host","$username","$password","$db_name");
if (mysqli_connect_errno())
{
echo "The application has failed to connect to the mysql database server: " .mysqli_connect_error();
}
$result = mysqli_query($connection, "SELECT * FROM fruits_tbl")or die("Error: " . mysqli_error($connection));
$num_rows=mysqli_num_rows($result);
$rows = $num_rows/3;
for($i=1; $i<=$rows ; $i++)
{
echo "<tr>";
for($j=1; $j<=3; $j++)
{
while($row = mysqli_fetch_array($result))
{
echo
("<td width='180px' height='200px'>"
."<div class = 'fruit_image'>"
."<img src='"
.$row['fruit_image']
."'/>"
."</div>"
."<div class = 'fruit_title'>"
.$row['fruit_name']
."</div>"
."</td>"
);
}
}
echo "</tr>";
}
mysqli_close($connection);
?>
</table>
</center>
</body>
</html>
The above code I created, contains two FOR loops. The script should count the number of rows in the table, and then divide by 3(the number of columns on each row in the HTML table). I wonder where I'm going wrong wit this code.
我创建的上述代码包含两个 FOR 循环。该脚本应计算表格中的行数，然后除以 3（HTML 表格中每行的列数）。我想知道这段代码哪里出错了。
回答by Sean
With your while($row = mysqli_fetch_array($result)){}inside your 1st for loop it will run through all your rows, before the outside loop runs 2nd/3rd time.
在您while($row = mysqli_fetch_array($result)){}的第一个 for 循环内部，它将在外部循环第二次/第三次运行之前遍历您的所有行。
Here is another way to do it -
这是另一种方法 -
$counter = 1;
// start 1st row
echo "<tr>";
while($row = mysqli_fetch_array($result)){
// if the 4th cell, end last row, and start new row
if ($counter%3==1){
echo "</tr><tr>";
}
echo
"<td width='180px' height='200px'>"
."<div class = 'fruit_image'>"
."<img src='"
.$row['fruit_image']
."'/>"
."</div>"
."<div class = 'fruit_title'>"
.$row['fruit_name']
."</div>"
."</td>";
// increase the counter
$counter++;
}
// close the last row
echo "</tr>";
回答by jcsanyi
You're looping through all the results in the first table cell. Try something like this instead:
您正在遍历第一个表格单元格中的所有结果。试试这样的：
for($i=1; $i<=$rows ; $i++) {
echo "<tr>";
for($j=1; $j<=3; $j++) {
$row = mysqli_fetch_array($result);
if ($row) {
echo(
"<td width='180px' height='200px'>"
."<div class = 'fruit_image'>"
."<img src='"
.$row['fruit_image']
."'/>"
."</div>"
."<div class = 'fruit_title'>"
.$row['fruit_name']
."</div>"
."</td>"
);
}
}
echo "</tr>";
}
回答by Revent
If you just want to format the display with a new row after every 3 records, you could use the modulus operator:
如果您只想在每 3 条记录后用新行格式化显示，您可以使用模数运算符：
$cntr = 0;
echo '<tr>';
while($row = mysqli_fetch_array($result)) {
$cntr++;
echo '
<td width="180px" height="200px">
<div class="fruit_image">
<img src="'.$row['fruit_image'].'" />
</div>
<div class="fruit_title">'.$row['fruit_name'].'</div>
</td>';
if ($cntr % 3 == 0 && $cntr != $num_rows)
echo '</tr><tr>';
}
echo '</tr>';
Keep in mind however that all the solutions presented so far may leave you with a last row with one or two td elements. You can fill this if you desire with empty <td> </td>columns.
但是请记住，到目前为止提供的所有解决方案可能会在最后一行留下一个或两个 td 元素。如果您需要空<td> </td>列，您可以填充它。
回答by rajratna maitry
print "<center><table border=1>
<tr>
<td>id</td>
<td>name</td>
<td>company</td>
<td>branch</td>
<td>job title</td>
<td>contact</td>
<td>email</td>
<td>mgs</td>
</tr>";
while($row=mysql_fetch_array($query))
{
print "<tr>";
for ($i=0;$i<=(count($row)/2);$i++)
{
print "<td>$row[$i]</td>";
} print"</tr>";
}
}
else{echo " <p>No Records Found</p>";}
回答by Mishari
<?php
function studentTable($name,$grade){
echo "<tr> <td>$name</td><td>$grade</td></tr>";
}
?>
<table style="width:100%" border="solid">
<tr>
<th>Name</th>
<th>Grade</th>
</tr>
<?php studentTable("Sarah", 90) ?>
