Javascript 如何在 JsDoc 中返回 void?
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How to return void in JsDoc?
提问by Tower
Is there a specified way to declare a method or a function to return void in JsDoc? Currently I am in the belief that void
is the default return value, and other return values must be specifically provided:
在 JsDoc 中是否有指定方法或函数来声明返回 void 的方法?目前我认为这void
是默认返回值,必须特别提供其他返回值:
/**
* @return {Integer} The identifier for ...
*/
回答by Brent Robinson
Closure Compiler
闭包编译器
According to the documentation of Google's Closure Compiler if nothing is being returned, the @return annotation should be omitted.
根据 Google's Closure Compiler 的文档,如果没有返回任何内容,则应省略 @return 注释。
If there is no return value, do not use a @return tag.
如果没有返回值,不要使用@return 标签。
Source:https://developers.google.com/closure/compiler/docs/js-for-compiler#tags
来源:https : //developers.google.com/closure/compiler/docs/js-for-compiler#tags
jsdoc-toolkit
jsdoc-工具包
However further documentation also states that the returnType and returnDescription are optional parameters.
然而,进一步的文档还指出 returnType 和 returnDescription 是可选参数。
returnType - Optional: the type of the return value.
returnDescription - Optional: any additional description.
returnType - 可选:返回值的类型。
returnDescription - 可选:任何附加说明。
Source:https://code.google.com/p/jsdoc-toolkit/wiki/TagReturns
来源:https : //code.google.com/p/jsdoc-toolkit/wiki/TagReturns
Summary
概括
You could either leave out the return annotation or include it without any parameters.
您可以省略返回注释,也可以不带任何参数包含它。
回答by David Tang
I don't believe you have to choose from a set of types in JsDoc... you can use any type name you wish (the curly braces indicate it's a type), so you can simply do:
我不相信您必须从 JsDoc 中的一组类型中进行选择……您可以使用任何您希望的类型名称(大括号表示它是一种类型),因此您可以简单地执行以下操作:
@return {Void}
Although, this is probably more correct for JavaScript:
虽然,这对于 JavaScript 来说可能更正确:
@return {undefined}
回答by primetimejas
Looking at the ESlint docs they use
@returns {void}
查看他们使用的 ESlint 文档
@returns {void}
Source: http://eslint.org/docs/rules/valid-jsdoc
来源:http: //eslint.org/docs/rules/valid-jsdoc
Since I need to provide an @returns
for each function to pass tests in order to push code for certain projects this is required in my case.
由于我需要@returns
为每个函数提供一个以通过测试以便为某些项目推送代码,因此在我的情况下这是必需的。
回答by Akseli Palén
If you need to say out loud that nothing is returned, you can say that in the free-form description. This is useful to clarify situations where a user might expect something to be returned. Of course proper naming of the function and the parametersshould alone make the expected return type apparent, but it might not always be possible.
如果您需要大声说不返回任何内容,可以在自由格式说明中说。这对于澄清用户可能期望返回某些内容的情况很有用。当然,函数和参数的正确命名应该单独使预期的返回类型显而易见,但这可能并不总是可能的。
/**
* This is a funny function. Returns nothing.
* @param {string} a joke.
*/
var funny = function (joke) {
console.log(joke);
};