wordpress 通过 id 获取摘录
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wordpress get excerpt by id
提问by Neros
I'm using the options framework
我正在使用选项框架
and i can't work out why this doesnt work
我不知道为什么这不起作用
$x = of_get_option('post_number');
$content_post = get_post($x);
echo $content_post->post_excerpt;
its very odd because
这很奇怪，因为
echo of_get_option('post_number');
works perfectly and outputs a number
完美运行并输出一个数字
and according to get_postmy code should work yet the echo produces nothing, not even an error message
并且根据get_post我的代码应该可以工作但回声什么也不产生，甚至没有错误消息
so i must be handeling get_post() incorrectly somehow, any clues?
所以我必须以某种方式错误地处理 get_post() ，有什么线索吗？
EDIT
编辑
var dump http://pastebin.com/ZEgQ5WPnreveals that post_content is full but post_excerpt is empty
var dump http://pastebin.com/ZEgQ5WPn显示 post_content 已满但 post_excerpt 为空
how do i regenerate the excerpt?
我如何重新生成摘录？
EDIT [resolved]
编辑 [已解决]
i decided to manualy overwrite the excerpt but my option was missing, then i found this
我决定手动覆盖摘录，但我的选项丢失了，然后我找到了这个
and used
并使用
add_post_type_support( 'page', 'excerpt' );
to manualy write the excerpt
手动编写摘录
回答by realmag777
$text = apply_filters('the_excerpt', get_post_field('post_excerpt', $post_id));
回答by heathhettig
This will take the post_content and create an excerpt out of it. You can substitute the post_content for any other string of code. Change the 55 to another number to increase the amount of words returned.
这将获取 post_content 并从中创建一个摘录。您可以将 post_content 替换为任何其他代码字符串。将 55 更改为另一个数字以增加返回的字数。
$excerpt = wp_trim_words ( strip_shortcodes( $recent["post_content"], 55 ) );
回答by buley
You should be able to use get_post()like this, which returnsalmost all built-in post attributes as part of the post object.
你应该能够像这样使用get_post()，它返回几乎所有内置的 post 属性作为 post 对象的一部分。
<?php
$my_id = 7;
$my_post = get_post( $my_id );
$my_excerpt = $my_post->post_excerpt;
var_dump( $my_excerpt );
?>
If that fails (it shouldn't, but perhaps you've tried by the sound of it) maybe checkout out WP_Queryand pass in "p=$my_id"as a param. This is likely the function used under the get_post hood anyways.
如果失败（它不应该，但也许你已经尝试过它的声音）可能签出WP_Query并"p=$my_id"作为参数传入。无论如何，这很可能是在 get_post 引擎盖下使用的函数。
<?php
$my_id = 7;
$my_posts = new WP_Query( "p=$my_id" );
var_dump( $my_posts );
?>
