Python：将列表转换为普通值
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Python: Convert a list into a normal value
提问by Bruce
I have a list
我有一个清单
a = [3]
print a
[3]
I want ot convert it into a normal integer
我想把它转换成一个普通的整数
print a
3
How do I do that?
我怎么做？
回答by YOU
a = a[0]
print a
3
Or are you looking for sum?
或者你在找sum什么？
>>> a=[1]
>>> sum(a)
1
>>> a=[1,2,3]
>>> sum(a)
6
回答by Alok Singhal
The problem is not clear. If ahas only one element, you can get it by:
问题不清楚。如果a只有一个元素，您可以通过以下方式获取：
a = a[0]
If it has more than one, then you need to specify how to get a number from more than one.
如果它有多个，那么您需要指定如何从多个中获取一个数字。
回答by brianray
I imagine there are many ways.
我想有很多方法。
If you want an int() you should cast it on each item in the list:
如果你想要一个 int() 你应该把它投射到列表中的每个项目上：
>>> a = [3,2,'1']
>>> while a: print int(a.pop())
1
2
3
That would also empty a and pop() off each back handle cases where they are strings.
这也将清空 a 和 pop() 每个后处理情况，其中它们是字符串。
You could also keep a untouched and just iterate over the items:
你也可以保持一个不变，只是迭代项目：
>>> a = [3,2,'1']
>>> for item in a: print int(item)
3
2
1
回答by Jesper Joachim S?rensen
To unpack a list you can use '*':
要解压缩列表，您可以使用“*”：
>>> a = [1, 4, 'f']
>>> print(*a)
1 4 f
