C++ 当前日期和时间作为字符串
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Current date and time as string
提问by Katie
I wrote a function to get a current date and time in format: DD-MM-YYYY HH:MM:SS. It works but let's say, its pretty ugly. How can I do exactly the same thingbut simpler?
我写了一个函数来获取当前日期和时间的格式：DD-MM-YYYY HH:MM:SS. 它有效，但让我们说，它非常丑陋。我怎样才能做完全相同但更简单的事情？
string currentDateToString()
{
time_t now = time(0);
tm *ltm = localtime(&now);
string dateString = "", tmp = "";
tmp = numToString(ltm->tm_mday);
if (tmp.length() == 1)
tmp.insert(0, "0");
dateString += tmp;
dateString += "-";
tmp = numToString(1 + ltm->tm_mon);
if (tmp.length() == 1)
tmp.insert(0, "0");
dateString += tmp;
dateString += "-";
tmp = numToString(1900 + ltm->tm_year);
dateString += tmp;
dateString += " ";
tmp = numToString(ltm->tm_hour);
if (tmp.length() == 1)
tmp.insert(0, "0");
dateString += tmp;
dateString += ":";
tmp = numToString(1 + ltm->tm_min);
if (tmp.length() == 1)
tmp.insert(0, "0");
dateString += tmp;
dateString += ":";
tmp = numToString(1 + ltm->tm_sec);
if (tmp.length() == 1)
tmp.insert(0, "0");
dateString += tmp;
return dateString;
}
回答by awesoon
Since C++11 you could use std::put_timefrom iomanipheader:
从 C++11 开始，您可以std::put_time从头iomanip文件中使用：
#include <iostream>
#include <iomanip>
#include <ctime>
int main()
{
auto t = std::time(nullptr);
auto tm = *std::localtime(&t);
std::cout << std::put_time(&tm, "%d-%m-%Y %H-%M-%S") << std::endl;
}
std::put_timeis a stream manipulator, therefore it could be used together with std::ostringstreamin order to convert the date to a string:
std::put_time是一个流操纵器，因此可以与它一起使用std::ostringstream以将日期转换为字符串：
#include <iostream>
#include <iomanip>
#include <ctime>
#include <sstream>
int main()
{
auto t = std::time(nullptr);
auto tm = *std::localtime(&t);
std::ostringstream oss;
oss << std::put_time(&tm, "%d-%m-%Y %H-%M-%S");
auto str = oss.str();
std::cout << str << std::endl;
}
回答by Max
Non C++11 solution: With the <ctime>header, you could use strftime. Make sure your buffer is large enough, you wouldn't want to overrun it and wreak havoc later.
非 C++11 解决方案：使用<ctime>标头，您可以使用strftime. 确保您的缓冲区足够大，您不希望它溢出并在以后造成严重破坏。
#include <iostream>
#include <ctime>
int main ()
{
time_t rawtime;
struct tm * timeinfo;
char buffer[80];
time (&rawtime);
timeinfo = localtime(&rawtime);
strftime(buffer,sizeof(buffer),"%d-%m-%Y %H:%M:%S",timeinfo);
std::string str(buffer);
std::cout << str;
return 0;
}
回答by birubisht
you can use asctime() function of time.h to get a string simply .
您可以使用 time.h 的 asctime() 函数来简单地获取字符串。
time_t _tm =time(NULL );
struct tm * curtime = localtime ( &_tm );
cout<<"The current date/time is:"<<asctime(curtime);
Sample output:
示例输出：
The current date/time is:Fri Oct 16 13:37:30 2015
回答by Black
Using C++ in MS Visual Studio 2015 (14), I use:
在 MS Visual Studio 2015 (14) 中使用 C++，我使用：
#include <chrono>
string NowToString()
{
chrono::system_clock::time_point p = chrono::system_clock::now();
time_t t = chrono::system_clock::to_time_t(p);
char str[26];
ctime_s(str, sizeof str, &t);
return str;
}
回答by AGG GAA
#include <chrono>
#include <iostream>
int main()
{
std::time_t ct = std::time(0);
char* cc = ctime(&ct);
std::cout << cc << std::endl;
return 0;
}
回答by DiB
I wanted to use the C++11 answer, but I could not because GCC 4.9 does not support std::put_time.
我想使用 C++11 答案，但我不能，因为 GCC 4.9 不支持 std::put_time。
std::put_time implementation status in GCC?
I ended up using some C++11 to slightly improve the non-C++11 answer. For those that can't use GCC 5, but would still like some C++11 in their date/time format:
我最终使用了一些 C++11 来稍微改进非 C++11 的答案。对于那些不能使用 GCC 5，但仍然想要一些 C++11 的日期/时间格式的人：
std::array<char, 64> buffer;
buffer.fill(0);
time_t rawtime;
time(&rawtime);
const auto timeinfo = localtime(&rawtime);
strftime(buffer.data(), sizeof(buffer), "%d-%m-%Y %H-%M-%S", timeinfo);
std::string timeStr(buffer.data());
