ios 获取两个 NSDates 之间的差异（月/天/小时/分钟/秒）
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Getting the difference between two NSDates in (months/days/hours/minutes/seconds)
提问by uhfocuz
I am trying to get the difference between the current date as NSDate()and a date from a PHP time();call for example: NSDate(timeIntervalSinceReferenceDate: 1417147270). How do I go about getting the difference in time between the two dates. I'd like to have a function that compares the two dates and if(seconds > 60)then it returns minutes, if(minutes > 60)return hours and if(hours > 24)return days and so on.
我试图让当前日期之间的差异NSDate()，并从PHP的日期time();呼吁例如：NSDate(timeIntervalSinceReferenceDate: 1417147270)。我如何获得两个日期之间的时间差。我想要一个函数来比较两个日期，if(seconds > 60)然后返回分钟、if(minutes > 60)返回小时和if(hours > 24)返回天等等。
How should I go about this?
我应该怎么做？
EDIT: The current accepted answer has done exactly what I've wanted to do. I recommend it for easy usage for getting the time between two dates in the form that that PHP time()function uses. If you aren't particularly familiar with PHP, that's the time in seconds from January 1st, 1970. This is beneficial for a backend in PHP. If perhaps you're using a backend like NodeJS you might want to consider some of the other options you'll find below.
编辑：当前接受的答案正是我想做的。我推荐它以便于使用 PHPtime()函数使用的形式获取两个日期之间的时间。如果您对 PHP 不是特别熟悉，那是从 1970 年 1 月 1 日开始的以秒为单位的时间。这对于 PHP 后端是有益的。如果您正在使用像 NodeJS 这样的后端，您可能需要考虑下面的一些其他选项。
回答by Leo Dabus
Xcode 8.3 ? Swift 3.1 or later
Xcode 8.3？Swift 3.1 或更高版本
You can use Calendar to help you create an extension to do your date calculations as follow:
您可以使用 Calendar 来帮助您创建一个扩展来进行日期计算，如下所示：
extension Date {
/// Returns the amount of years from another date
func years(from date: Date) -> Int {
return Calendar.current.dateComponents([.year], from: date, to: self).year ?? 0
}
/// Returns the amount of months from another date
func months(from date: Date) -> Int {
return Calendar.current.dateComponents([.month], from: date, to: self).month ?? 0
}
/// Returns the amount of weeks from another date
func weeks(from date: Date) -> Int {
return Calendar.current.dateComponents([.weekOfMonth], from: date, to: self).weekOfMonth ?? 0
}
/// Returns the amount of days from another date
func days(from date: Date) -> Int {
return Calendar.current.dateComponents([.day], from: date, to: self).day ?? 0
}
/// Returns the amount of hours from another date
func hours(from date: Date) -> Int {
return Calendar.current.dateComponents([.hour], from: date, to: self).hour ?? 0
}
/// Returns the amount of minutes from another date
func minutes(from date: Date) -> Int {
return Calendar.current.dateComponents([.minute], from: date, to: self).minute ?? 0
}
/// Returns the amount of seconds from another date
func seconds(from date: Date) -> Int {
return Calendar.current.dateComponents([.second], from: date, to: self).second ?? 0
}
/// Returns the a custom time interval description from another date
func offset(from date: Date) -> String {
if years(from: date) > 0 { return "\(years(from: date))y" }
if months(from: date) > 0 { return "\(months(from: date))M" }
if weeks(from: date) > 0 { return "\(weeks(from: date))w" }
if days(from: date) > 0 { return "\(days(from: date))d" }
if hours(from: date) > 0 { return "\(hours(from: date))h" }
if minutes(from: date) > 0 { return "\(minutes(from: date))m" }
if seconds(from: date) > 0 { return "\(seconds(from: date))s" }
return ""
}
}
Using Date Components Formatter
使用日期组件格式化程序
let dateComponentsFormatter = DateComponentsFormatter()
dateComponentsFormatter.allowedUnits = [.year,.month,.weekOfMonth,.day,.hour,.minute,.second]
dateComponentsFormatter.maximumUnitCount = 1
dateComponentsFormatter.unitsStyle = .full
dateComponentsFormatter.string(from: Date(), to: Date(timeIntervalSinceNow: 4000000)) // "1 month"
let date1 = DateComponents(calendar: .current, year: 2014, month: 11, day: 28, hour: 5, minute: 9).date!
let date2 = DateComponents(calendar: .current, year: 2015, month: 8, day: 28, hour: 5, minute: 9).date!
let years = date2.years(from: date1) // 0
let months = date2.months(from: date1) // 9
let weeks = date2.weeks(from: date1) // 39
let days = date2.days(from: date1) // 273
let hours = date2.hours(from: date1) // 6,553
let minutes = date2.minutes(from: date1) // 393,180
let seconds = date2.seconds(from: date1) // 23,590,800
let timeOffset = date2.offset(from: date1) // "9M"
let date3 = DateComponents(calendar: .current, year: 2014, month: 11, day: 28, hour: 5, minute: 9).date!
let date4 = DateComponents(calendar: .current, year: 2015, month: 11, day: 28, hour: 5, minute: 9).date!
let timeOffset2 = date4.offset(from: date3) // "1y"
let date5 = DateComponents(calendar: .current, year: 2017, month: 4, day: 28).date!
let now = Date()
let timeOffset3 = now.offset(from: date5) // "1w"
回答by Adam Studenic
If someone needs to display all time units e.g "hours minutes seconds" not just "hours". Let's say the time difference between two dates is 1hour 59minutes 20seconds. This function will display "1h 59m 20s".
如果有人需要显示所有时间单位，例如“小时分秒”而不仅仅是“小时”。假设两个日期之间的时差是 1 小时 59 分 20 秒。此功能将显示“1h 59m 20s”。
Here is my Objective-C code:
这是我的 Objective-C 代码：
extension NSDate {
func offsetFrom(date: NSDate) -> String {
let dayHourMinuteSecond: NSCalendarUnit = [.Day, .Hour, .Minute, .Second]
let difference = NSCalendar.currentCalendar().components(dayHourMinuteSecond, fromDate: date, toDate: self, options: [])
let seconds = "\(difference.second)s"
let minutes = "\(difference.minute)m" + " " + seconds
let hours = "\(difference.hour)h" + " " + minutes
let days = "\(difference.day)d" + " " + hours
if difference.day > 0 { return days }
if difference.hour > 0 { return hours }
if difference.minute > 0 { return minutes }
if difference.second > 0 { return seconds }
return ""
}
}
In Swift 3+:
在 Swift 3+ 中：
extension Date {
func offsetFrom(date: Date) -> String {
let dayHourMinuteSecond: Set<Calendar.Component> = [.day, .hour, .minute, .second]
let difference = NSCalendar.current.dateComponents(dayHourMinuteSecond, from: date, to: self)
let seconds = "\(difference.second ?? 0)s"
let minutes = "\(difference.minute ?? 0)m" + " " + seconds
let hours = "\(difference.hour ?? 0)h" + " " + minutes
let days = "\(difference.day ?? 0)d" + " " + hours
if let day = difference.day, day > 0 { return days }
if let hour = difference.hour, hour > 0 { return hours }
if let minute = difference.minute, minute > 0 { return minutes }
if let second = difference.second, second > 0 { return seconds }
return ""
}
}
回答by Rob
You ask:
你问：
I'd like to have a function that compares the two dates and if(seconds > 60) then it returns minutes, if(minutes > 60) return hours and if(hours > 24) return days and so on.
我想要一个函数来比较两个日期和 if(seconds > 60) 然后它返回分钟， if(minutes > 60) return hours 和 if(hours > 24) return days 等等。
I'm assuming that you're trying to build a string representation of the elapsed time between two dates. Rather than writing your own code to do that, Apple already has a class designed to do precisely that. Namely, use DateComponentsFormatter, set allowedUnitsto whatever values make sense to your app, set unitsStyleto whatever you want (e.g. .full), and then call string(from:to:).
我假设您正在尝试构建两个日期之间经过时间的字符串表示形式。与其编写自己的代码来做到这一点，Apple 已经有一个专为做到这一点而设计的类。即，使用DateComponentsFormatter, 设置allowedUnits为对您的应用程序有意义的任何值，设置unitsStyle为您想要的任何值（例如.full），然后调用string(from:to:).
E.g. in Swift 3:
例如在 Swift 3 中：
let previousDate = ...
let now = Date()
let formatter = DateComponentsFormatter()
formatter.unitsStyle = .full
formatter.allowedUnits = [.month, .day, .hour, .minute, .second]
formatter.maximumUnitCount = 2 // often, you don't care about seconds if the elapsed time is in months, so you'll set max unit to whatever is appropriate in your case
let string = formatter.string(from: previousDate, to: now)
This also will localize the string appropriate for the device in question.
这也将本地化适合相关设备的字符串。
Or, in Swift 2.3:
或者，在 Swift 2.3 中：
let previousDate = ...
let now = NSDate()
let formatter = NSDateComponentsFormatter()
formatter.unitsStyle = .Full
formatter.allowedUnits = [.Month, .Day, .Hour, .Minute, .Second]
formatter.maximumUnitCount = 2
let string = formatter.stringFromDate(previousDate, toDate: now)
If you're looking for the actual numeric values, just use dateComponents. E.g. in Swift 3:
如果您正在寻找实际的数值，只需使用dateComponents. 例如在 Swift 3 中：
let components = Calendar.current.dateComponents([.month, .day, .hour, .minute, .second], from: previousDate, to: now)
Or, in Swift 2.3:
或者，在 Swift 2.3 中：
let components = NSCalendar.currentCalendar().components([.Month, .Day, .Hour, .Minute, .Second], fromDate: previousDate, toDate: now, options: [])
回答by Adam Smaka
combined Extension + DateComponentsFormatter from the answer of @leo-dabus
来自@leo-dabus 的答案的组合扩展 + DateComponentsFormatter
Xcode 8.3 ? Swift 3.1
Xcode 8.3？斯威夫特 3.1
extension DateComponentsFormatter {
func difference(from fromDate: Date, to toDate: Date) -> String? {
self.allowedUnits = [.year,.month,.weekOfMonth,.day]
self.maximumUnitCount = 1
self.unitsStyle = .full
return self.string(from: fromDate, to: toDate)
}
}
let dateComponentsFormatter = DateComponentsFormatter()
dateComponentsFormatter.difference(from: Date(), to: Date(timeIntervalSinceNow: 4000000)) // "1 month"
回答by Ayush jain
--> Use this to find time gap between two dates in Swift(With two Strings).
--> 使用它来查找Swift 中两个日期之间的时间间隔（使用两个字符串）。
func timeGapBetweenDates(previousDate : String,currentDate : String)
{
let dateString1 = previousDate
let dateString2 = currentDate
let Dateformatter = DateFormatter()
Dateformatter.dateFormat = "yyyy-MM-dd HH:mm:ss"
let date1 = Dateformatter.date(from: dateString1)
let date2 = Dateformatter.date(from: dateString2)
let distanceBetweenDates: TimeInterval? = date2?.timeIntervalSince(date1!)
let secondsInAnHour: Double = 3600
let minsInAnHour: Double = 60
let secondsInDays: Double = 86400
let secondsInWeek: Double = 604800
let secondsInMonths : Double = 2592000
let secondsInYears : Double = 31104000
let minBetweenDates = Int((distanceBetweenDates! / minsInAnHour))
let hoursBetweenDates = Int((distanceBetweenDates! / secondsInAnHour))
let daysBetweenDates = Int((distanceBetweenDates! / secondsInDays))
let weekBetweenDates = Int((distanceBetweenDates! / secondsInWeek))
let monthsbetweenDates = Int((distanceBetweenDates! / secondsInMonths))
let yearbetweenDates = Int((distanceBetweenDates! / secondsInYears))
let secbetweenDates = Int(distanceBetweenDates!)
if yearbetweenDates > 0
{
print(yearbetweenDates,"years")//0 years
}
else if monthsbetweenDates > 0
{
print(monthsbetweenDates,"months")//0 months
}
else if weekBetweenDates > 0
{
print(weekBetweenDates,"weeks")//0 weeks
}
else if daysBetweenDates > 0
{
print(daysBetweenDates,"days")//5 days
}
else if hoursBetweenDates > 0
{
print(hoursBetweenDates,"hours")//120 hours
}
else if minBetweenDates > 0
{
print(minBetweenDates,"minutes")//7200 minutes
}
else if secbetweenDates > 0
{
print(secbetweenDates,"seconds")//seconds
}
}
回答by zumzum
I added a "long" version to Leo Dabus's asnwer in case you want to have a string that says something like "2 weeks ago" instead of just "2w"...
我在 Leo Dabus 的 asnwer 中添加了一个“长”版本，以防您想要一个字符串，上面写着“2 周前”而不是“2w”……
extension Date {
/// Returns the amount of years from another date
func years(from date: Date) -> Int {
return Calendar.current.dateComponents([.year], from: date, to: self).year ?? 0
}
/// Returns the amount of months from another date
func months(from date: Date) -> Int {
return Calendar.current.dateComponents([.month], from: date, to: self).month ?? 0
}
/// Returns the amount of weeks from another date
func weeks(from date: Date) -> Int {
return Calendar.current.dateComponents([.weekOfYear], from: date, to: self).weekOfYear ?? 0
}
/// Returns the amount of days from another date
func days(from date: Date) -> Int {
return Calendar.current.dateComponents([.day], from: date, to: self).day ?? 0
}
/// Returns the amount of hours from another date
func hours(from date: Date) -> Int {
return Calendar.current.dateComponents([.hour], from: date, to: self).hour ?? 0
}
/// Returns the amount of minutes from another date
func minutes(from date: Date) -> Int {
return Calendar.current.dateComponents([.minute], from: date, to: self).minute ?? 0
}
/// Returns the amount of seconds from another date
func seconds(from date: Date) -> Int {
return Calendar.current.dateComponents([.second], from: date, to: self).second ?? 0
}
/// Returns the a custom time interval description from another date
func offset(from date: Date) -> String {
if years(from: date) > 0 { return "\(years(from: date))y" }
if months(from: date) > 0 { return "\(months(from: date))M" }
if weeks(from: date) > 0 { return "\(weeks(from: date))w" }
if days(from: date) > 0 { return "\(days(from: date))d" }
if hours(from: date) > 0 { return "\(hours(from: date))h" }
if minutes(from: date) > 0 { return "\(minutes(from: date))m" }
if seconds(from: date) > 0 { return "\(seconds(from: date))s" }
return ""
}
func offsetLong(from date: Date) -> String {
if years(from: date) > 0 { return years(from: date) > 1 ? "\(years(from: date)) years ago" : "\(years(from: date)) year ago" }
if months(from: date) > 0 { return months(from: date) > 1 ? "\(months(from: date)) months ago" : "\(months(from: date)) month ago" }
if weeks(from: date) > 0 { return weeks(from: date) > 1 ? "\(weeks(from: date)) weeks ago" : "\(weeks(from: date)) week ago" }
if days(from: date) > 0 { return days(from: date) > 1 ? "\(days(from: date)) days ago" : "\(days(from: date)) day ago" }
if hours(from: date) > 0 { return hours(from: date) > 1 ? "\(hours(from: date)) hours ago" : "\(hours(from: date)) hour ago" }
if minutes(from: date) > 0 { return minutes(from: date) > 1 ? "\(minutes(from: date)) minutes ago" : "\(minutes(from: date)) minute ago" }
if seconds(from: date) > 0 { return seconds(from: date) > 1 ? "\(seconds(from: date)) seconds ago" : "\(seconds(from: date)) second ago" }
return ""
}
}
回答by jose920405
func dateDiff(dateStr:String) -> String {
var f:NSDateFormatter = NSDateFormatter()
f.timeZone = NSTimeZone.localTimeZone()
f.dateFormat = "yyyy-M-dd'T'HH:mm:ss.SSSZZZ"
var now = f.stringFromDate(NSDate())
var startDate = f.dateFromString(dateStr)
var endDate = f.dateFromString(now)
var calendar: NSCalendar = NSCalendar.currentCalendar()
let calendarUnits = NSCalendarUnit.CalendarUnitWeekOfMonth | NSCalendarUnit.CalendarUnitDay | NSCalendarUnit.CalendarUnitHour | NSCalendarUnit.CalendarUnitMinute | NSCalendarUnit.CalendarUnitSecond
let dateComponents = calendar.components(calendarUnits, fromDate: startDate!, toDate: endDate!, options: nil)
let weeks = abs(dateComponents.weekOfMonth)
let days = abs(dateComponents.day)
let hours = abs(dateComponents.hour)
let min = abs(dateComponents.minute)
let sec = abs(dateComponents.second)
var timeAgo = ""
if (sec > 0){
if (sec > 1) {
timeAgo = "\(sec) Seconds Ago"
} else {
timeAgo = "\(sec) Second Ago"
}
}
if (min > 0){
if (min > 1) {
timeAgo = "\(min) Minutes Ago"
} else {
timeAgo = "\(min) Minute Ago"
}
}
if(hours > 0){
if (hours > 1) {
timeAgo = "\(hours) Hours Ago"
} else {
timeAgo = "\(hours) Hour Ago"
}
}
if (days > 0) {
if (days > 1) {
timeAgo = "\(days) Days Ago"
} else {
timeAgo = "\(days) Day Ago"
}
}
if(weeks > 0){
if (weeks > 1) {
timeAgo = "\(weeks) Weeks Ago"
} else {
timeAgo = "\(weeks) Week Ago"
}
}
print("timeAgo is===> \(timeAgo)")
return timeAgo;
}
回答by Sagar Desai
Slightly modified code for Swift 3.0
对Swift 3.0稍加修改的代码
let calendar = NSCalendar.current as NSCalendar
// Replace the hour (time) of both dates with 00:00
let date1 = calendar.startOfDay(for: startDateTime)
let date2 = calendar.startOfDay(for: endDateTime)
let flags = NSCalendar.Unit.day
let components = calendar.components(flags, from: date1, to: date2, options: [])
return components.day!
回答by Marián ?erny
Swift 5.1 ? iOS 13
斯威夫特 5.1 ? iOS 13
You can use RelativeDateFormatterthat has been introduced by Apple in iOS 13.
您可以使用Apple 在 iOS 13 中引入的RelativeDateFormatter。
let exampleDate = Date().addingTimeInterval(-15000)
let formatter = RelativeDateTimeFormatter()
formatter.unitsStyle = .full
let relativeDate = formatter.localizedString(for: exampleDate, relativeTo: Date())
print(relativeDate) // 4 hours ago
See How to show a relative date and time using RelativeDateTimeFormatter.
回答by Mohsin Qureshi
In Swift 2.2
在 Swift 2.2 中
/// Returns the amount of years from another date
func years(fromdate: NSDate) -> Int {
return NSCalendar.currentCalendar().components([.Year], fromDate: fromdate, toDate: NSDate(), options: []).year ?? 0
}
/// Returns the amount of months from another date
func months(fromdate: NSDate) -> Int {
return NSCalendar.currentCalendar().components([.Month], fromDate: fromdate, toDate: NSDate(), options: []).month ?? 0
}
/// Returns the amount of weeks from another date
func weeks(fromdate: NSDate) -> Int {
return NSCalendar.currentCalendar().components([.WeekOfYear], fromDate: fromdate, toDate: NSDate(), options: []).weekOfYear ?? 0
}
/// Returns the amount of days from another date
func days(fromdate: NSDate) -> Int {
return NSCalendar.currentCalendar().components([.Day], fromDate: fromdate, toDate: NSDate(), options: []).day ?? 0
}
/// Returns the amount of hours from another date
func hours(fromdate: NSDate) -> Int {
return NSCalendar.currentCalendar().components([.Hour], fromDate: fromdate, toDate: NSDate(), options: []).hour ?? 0
}
/// Returns the amount of minutes from another date
func minutes(fromdate: NSDate) -> Int {
return NSCalendar.currentCalendar().components([.Minute], fromDate: fromdate, toDate: NSDate(), options: []).minute ?? 0
}
/// Returns the amount of seconds from another date
func seconds(fromdate: NSDate) -> Int {
return NSCalendar.currentCalendar().components(.Second, fromDate: fromdate, toDate: NSDate(), options: []).second ?? 0
}
