Ruby-on-rails 按整数值对字符串数组进行排序
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/7726968/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Sort an Array of Strings by their Integer Values
提问by tob88
Let's say I have an unsorted array from 1 to 10, as shown below...
假设我有一个从 1 到 10 的未排序数组，如下所示......
a = ["3", "5", "8", "4", "1", "2", "9", "10", "7", "6"]
If I use the sort method on this array, it returns this...
如果我在这个数组上使用 sort 方法，它会返回这个......
a.sort = ["1", "10", "2", "3", "4", "5", "6", "7", "8", "9"]
As you can see, the 10, appears before the 2, which is incorrect. How can I sort these numbers so that 10 appears correctly?
如您所见，10 出现在 2 之前，这是不正确的。如何对这些数字进行排序，以便 10 正确显示？
EDIT: Hi guys, thank you all for your responses. I should explain my problem a little better. The array I need sorted is for an e-commerce price list. So the array appears as follows...
编辑：大家好，谢谢大家的回复。我应该更好地解释我的问题。我需要排序的数组用于电子商务价格表。所以数组如下所示......
a = ["0-10", "11-20", "21-30", "31-40" etc.]
So the strings cannot be converted to integers. I should have put this when I wrote the question. I did not think that there would be much difference in the fix. My mistake, I apologise for making this assumption! How though can I sort this array? Thanks!
所以字符串不能转换为整数。当我写这个问题时，我应该把这个写出来。我不认为修复会有太大差异。我的错误，我为做出这个假设而道歉！我怎样才能对这个数组进行排序？谢谢！
回答by Wizard of Ogz
I'll throw another method out there since it's the shortest way I can think of
我会抛出另一种方法，因为这是我能想到的最短方法
a.sort_by(&:to_i)
回答by apneadiving
As your updated question states:
正如您更新的问题所述：
array.sort_by {|elt| ary = elt.split("-").map(&:to_i); ary[0] + ary[1]}
even geekier:
更极客：
array.sort_by {|elt| ary = elt.split("-").map(&:to_i).inject(&:+)}
回答by Matt
If you convert all strings to integers beforehand, it should work as expected:
如果事先将所有字符串转换为整数，它应该按预期工作：
a.map(&:to_i).sort
=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
回答by bricker
a.sort { |a,b| a.to_i <=> b.to_i }
回答by Jéssica Antunes
Another option, that can be used in your example or others arrays like
另一个选项，可用于您的示例或其他数组，如
a = ["teste", "test", "teste2", "tes3te", "10teste"]
is:
是：
a.sort_by! {|s| s[/\d+/].to_i}
回答by Paul Sasik
The reason for this behavior is that you have an array of strings and the sort that is being applied is string-based. To get the proper, numeric, sorting you have to convert the strings to numbers or just keep them as numbers in the first place. Is there a reason that your array is being populate with strings like this:
这种行为的原因是您有一个字符串数组，并且正在应用的排序是基于字符串的。要获得正确的数字排序，您必须将字符串转换为数字，或者首先将它们保留为数字。您的数组是否有这样的字符串填充的原因：
a = ["3", "5", "8", "4", "1", "2", "9", "10", "7", "6"]
Rather than numbers like this:
而不是这样的数字：
a = [3, 5, 8, 4, 1, 2, 9, 1, 7, 6]
?
?
回答by Thom
The cheap way would be to zero fill on the left and make all numbers 2 digit.
便宜的方法是在左侧填充零并使所有数字为 2 位。
