PHP：返回数组中两个日期之间的所有日期
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PHP: Return all dates between two dates in an array
提问by HyderA
Expected Input:
预期输入：
getDatesFromRange( '2010-10-01', '2010-10-05' );
Expected Output:
预期输出：
Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )
回答by ViNce
You could also take a look at the DatePeriodclass:
您还可以查看DatePeriod类：
$period = new DatePeriod(
new DateTime('2010-10-01'),
new DateInterval('P1D'),
new DateTime('2010-10-05')
);
Which should get you an array with DateTime objects.
这应该为您提供一个包含 DateTime 对象的数组。
To iterate
迭代
foreach ($period as $key => $value) {
//$value->format('Y-m-d')
}
回答by RobertPitt
function createDateRangeArray($strDateFrom,$strDateTo)
{
// takes two dates formatted as YYYY-MM-DD and creates an
// inclusive array of the dates between the from and to dates.
// could test validity of dates here but I'm already doing
// that in the main script
$aryRange=array();
$iDateFrom=mktime(1,0,0,substr($strDateFrom,5,2), substr($strDateFrom,8,2),substr($strDateFrom,0,4));
$iDateTo=mktime(1,0,0,substr($strDateTo,5,2), substr($strDateTo,8,2),substr($strDateTo,0,4));
if ($iDateTo>=$iDateFrom)
{
array_push($aryRange,date('Y-m-d',$iDateFrom)); // first entry
while ($iDateFrom<$iDateTo)
{
$iDateFrom+=86400; // add 24 hours
array_push($aryRange,date('Y-m-d',$iDateFrom));
}
}
return $aryRange;
}
source: http://boonedocks.net/mike/archives/137-Creating-a-Date-Range-Array-with-PHP.html
来源：http: //boonedocks.net/mike/archives/137-Creating-a-Date-Range-Array-with-PHP.html
回答by alioygur
This is very very flexible.
这是非常非常灵活的。
/**
* Creating date collection between two dates
*
* <code>
* <?php
* # Example 1
* date_range("2014-01-01", "2014-01-20", "+1 day", "m/d/Y");
*
* # Example 2. you can use even time
* date_range("01:00:00", "23:00:00", "+1 hour", "H:i:s");
* </code>
*
* @author Ali OYGUR <[email protected]>
* @param string since any date, time or datetime format
* @param string until any date, time or datetime format
* @param string step
* @param string date of output format
* @return array
*/
function date_range($first, $last, $step = '+1 day', $output_format = 'd/m/Y' ) {
$dates = array();
$current = strtotime($first);
$last = strtotime($last);
while( $current <= $last ) {
$dates[] = date($output_format, $current);
$current = strtotime($step, $current);
}
return $dates;
}
回答by Maxime
Note that the answer provided by ViNce does NOT include the end datefor the period.
请注意，ViNce 提供的答案不包括该期间的结束日期。
If you are using PHP 5.3+, your best bet is to use a function like this:
如果您使用的是 PHP 5.3+，最好的办法是使用这样的函数：
/**
* Generate an array of string dates between 2 dates
*
* @param string $start Start date
* @param string $end End date
* @param string $format Output format (Default: Y-m-d)
*
* @return array
*/
function getDatesFromRange($start, $end, $format = 'Y-m-d') {
$array = array();
$interval = new DateInterval('P1D');
$realEnd = new DateTime($end);
$realEnd->add($interval);
$period = new DatePeriod(new DateTime($start), $interval, $realEnd);
foreach($period as $date) {
$array[] = $date->format($format);
}
return $array;
}
Then, you would call the function as expected:
然后，您将按预期调用该函数：
getDatesFromRange('2010-10-01', '2010-10-05');
Note about DatePeriodclass: You can use the 4th parameter of DatePeriod to exclude the start date (DatePeriod::EXCLUDE_START_DATE) but you cannot, at this time, include the end date.
关于DatePeriodclass 的注意事项：您可以使用 DatePeriod 的第 4 个参数来排除开始日期 ( DatePeriod::EXCLUDE_START_DATE)，但此时您不能包括结束日期。
回答by Victor Azevedo
Simple but like a charm:
简单但就像一个魅力：
$period = new DatePeriod(new DateTime('2015-01-01'), new DateInterval('P1D'), new DateTime('2015-01-15 +1 day'));
foreach ($period as $date) {
$dates[] = $date->format("Y-m-d");
}
//ONLY SHOWING
echo '<pre>';
var_dump($dates);
echo '</pre>';
exit();
回答by drolex
This is short, sweet, and should work in PHP4+.
这是简短的，甜蜜的，应该在 PHP4+ 中工作。
function getDatesFromRange($start, $end){
$dates = array($start);
while(end($dates) < $end){
$dates[] = date('Y-m-d', strtotime(end($dates).' +1 day'));
}
return $dates;
}
回答by Haim Evgi
function GetDays($sStartDate, $sEndDate){
// Firstly, format the provided dates.
// This function works best with YYYY-MM-DD
// but other date formats will work thanks
// to strtotime().
$sStartDate = gmdate("Y-m-d", strtotime($sStartDate));
$sEndDate = gmdate("Y-m-d", strtotime($sEndDate));
// Start the variable off with the start date
$aDays[] = $sStartDate;
// Set a 'temp' variable, sCurrentDate, with
// the start date - before beginning the loop
$sCurrentDate = $sStartDate;
// While the current date is less than the end date
while($sCurrentDate < $sEndDate){
// Add a day to the current date
$sCurrentDate = gmdate("Y-m-d", strtotime("+1 day", strtotime($sCurrentDate)));
// Add this new day to the aDays array
$aDays[] = $sCurrentDate;
}
// Once the loop has finished, return the
// array of days.
return $aDays;
}
use like
使用喜欢
GetDays('2007-01-01', '2007-01-31');
回答by Lukas Liesis
many ways of getting this done, but finally it all depends on PHP version you are using. Here is summary of all solutions:
完成此操作的多种方法，但最终这一切都取决于您使用的 PHP 版本。以下是所有解决方案的摘要：
get PHP version:
获取 PHP 版本：
echo phpinfo();
PHP 5.3+
PHP 5.3+
$period = new DatePeriod(
new DateTime('2010-10-01'),
new DateInterval('P1D'),
new DateTime('2010-10-05')
);
PHP 4+
PHP 4+
/**
* creating between two date
* @param string since
* @param string until
* @param string step
* @param string date format
* @return array
* @author Ali OYGUR <[email protected]>
*/
function dateRange($first, $last, $step = '+1 day', $format = 'd/m/Y' ) {
$dates = array();
$current = strtotime($first);
$last = strtotime($last);
while( $current <= $last ) {
$dates[] = date($format, $current);
$current = strtotime($step, $current);
}
return $dates;
}
PHP < 4
PHP < 4
you should upgrade :)
你应该升级:)
回答by nzn
Short function. PHP 5.3 and up. Can take optional third param of any date format that strtotime can understand. Automatically reverses direction if end < start.
短功能。PHP 5.3 及更高版本。可以采用 strtotime 可以理解的任何日期格式的可选第三个参数。如果结束 < 开始，则自动反转方向。
function getDatesFromRange($start, $end, $format='Y-m-d') {
return array_map(function($timestamp) use($format) {
return date($format, $timestamp);
},
range(strtotime($start) + ($start < $end ? 4000 : 8000), strtotime($end) + ($start < $end ? 8000 : 4000), 86400));
}
Test:
测试：
date_default_timezone_set('Europe/Berlin');
print_r(getDatesFromRange( '2016-7-28','2016-8-2' ));
print_r(getDatesFromRange( '2016-8-2','2016-7-28' ));
print_r(getDatesFromRange( '2016-10-28','2016-11-2' ));
print_r(getDatesFromRange( '2016-11-2','2016-10-28' ));
print_r(getDatesFromRange( '2016-4-2','2016-3-25' ));
print_r(getDatesFromRange( '2016-3-25','2016-4-2' ));
print_r(getDatesFromRange( '2016-8-2','2016-7-25' ));
print_r(getDatesFromRange( '2016-7-25','2016-8-2' ));
Output:
输出：
Array ( [0] => 2016-07-28 [1] => 2016-07-29 [2] => 2016-07-30 [3] => 2016-07-31 [4] => 2016-08-01 [5] => 2016-08-02 )
Array ( [0] => 2016-08-02 [1] => 2016-08-01 [2] => 2016-07-31 [3] => 2016-07-30 [4] => 2016-07-29 [5] => 2016-07-28 )
Array ( [0] => 2016-10-28 [1] => 2016-10-29 [2] => 2016-10-30 [3] => 2016-10-31 [4] => 2016-11-01 [5] => 2016-11-02 )
Array ( [0] => 2016-11-02 [1] => 2016-11-01 [2] => 2016-10-31 [3] => 2016-10-30 [4] => 2016-10-29 [5] => 2016-10-28 )
Array ( [0] => 2016-04-02 [1] => 2016-04-01 [2] => 2016-03-31 [3] => 2016-03-30 [4] => 2016-03-29 [5] => 2016-03-28 [6] => 2016-03-27 [7] => 2016-03-26 [8] => 2016-03-25 )
Array ( [0] => 2016-03-25 [1] => 2016-03-26 [2] => 2016-03-27 [3] => 2016-03-28 [4] => 2016-03-29 [5] => 2016-03-30 [6] => 2016-03-31 [7] => 2016-04-01 [8] => 2016-04-02 )
Array ( [0] => 2016-08-02 [1] => 2016-08-01 [2] => 2016-07-31 [3] => 2016-07-30 [4] => 2016-07-29 [5] => 2016-07-28 [6] => 2016-07-27 [7] => 2016-07-26 [8] => 2016-07-25 )
Array ( [0] => 2016-07-25 [1] => 2016-07-26 [2] => 2016-07-27 [3] => 2016-07-28 [4] => 2016-07-29 [5] => 2016-07-30 [6] => 2016-07-31 [7] => 2016-08-01 [8] => 2016-08-02 )
回答by Alex Joe
You mustadd $end->modify('+1 day')to include last day of interval, for example the January will have a 31 days instead of 30 without using modify() method. This version of code will include the last day of the interval:
您必须添加$end->modify('+1 day')以包含 interval 的最后一天，例如，一月将有 31 天而不是 30 天而不使用 modify() 方法。此版本的代码将包括间隔的最后一天：
$begin = new DateTime( '2018-08-01' );
$end = new DateTime( '2018-08-31' );
$end = $end->modify( '+1 day' );
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);
foreach($daterange as $date){
echo $date->format("Ymd") . "<br>";
}
