nodejs中的文件路径和删除文件
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file path and delete file in nodejs
提问by user3044147
I want to delete 3 files in list_file_to_deletebut I do not know what is the path to put to "path to three files here"?. Do I need for loop/for in/forEach function to delete all or just need a string with 3 paths likely var string = "...a1.jpg, ...a2.jpg,...a3.jpg"? Thanks in advance
我想删除其中的 3 个文件，list_file_to_delete但我不知道“此处的三个文件的路径”的路径是什么？。我是否需要 for loop/for in/forEach 函数来删除全部或只需要一个可能有 3 个路径的字符串var string = "...a1.jpg, ...a2.jpg,...a3.jpg"？提前致谢
in delete.jsfile
在delete.js文件中
var list_file_to_delete = ["/images/a1.jpg", "/images/a2.jpg", "/images/a3.jpg"]
fs.unlink(path to three files here, function(err) {console.log("success")})
this is myappdirectory
这是myapp目录
myapp
/app
/js
delete.js
/public
/images
a1.jpg
a2.jpg
a3.jpg
server.js
回答by Mike 'Pomax' Kamermans
fs.unlinktakes a single file, so unlink each element:
fs.unlink采用单个文件，因此取消链接每个元素：
list_of_files.forEach(function(filename) {
fs.unlink(filename);
});
or, if you need sequential, but asynchronous deletes you can use the following ES5 code:
或者，如果您需要顺序但异步的删除，您可以使用以下 ES5 代码：
(function next(err, list) {
if (err) {
return console.error("error in next()", err);
}
if (list.length === 0) {
return;
}
var filename = list.splice(0,1)[0];
fs.unlink(filename, function(err, result) {
next(err, list);
});
}(null, list_of_files.slice()));
