用Java初始化多维数组

Initialising a multidimensional array in Java

提问by burntsugar

What is the correct way to declare a multidimensional array and assign values to it?

声明多维数组并为其赋值的正确方法是什么？

This is what I have:

这就是我所拥有的：

int x = 5;
int y = 5;

String[][] myStringArray = new String [x][y];

myStringArray[0][x] = "a string";
myStringArray[0][y] = "another string";

采纳答案by jameshales

Try replacing the appropriate lines with:

尝试将适当的行替换为：

myStringArray[0][x-1] = "a string";
myStringArray[0][y-1] = "another string";

Your code is incorrect because the sub-arrays have a length of y, and indexing starts at 0. So setting to myStringArray[0][y]or myStringArray[0][x]will fail because the indices xand yare out of bounds.

您的代码不正确，因为子数组的长度为y，并且索引从 0 开始。因此设置为myStringArray[0][y]ormyStringArray[0][x]将失败，因为索引x和y超出范围。

String[][] myStringArray = new String [x][y];is the correct way to initialise a rectangular multidimensional array. If you want it to be jagged (each sub-array potentially has a different length) then you can use code similar to this answer. Note however that John's assertion that you have to create the sub-arrays manually is incorrect in the case where you want a perfectly rectangular multidimensional array.

String[][] myStringArray = new String [x][y];是初始化矩形多维数组的正确方法。如果您希望它是锯齿状的（每个子数组可能具有不同的长度），那么您可以使用类似于此答案的代码。但是请注意，在您想要一个完美的矩形多维数组的情况下，约翰关于您必须手动创建子数组的断言是不正确的。

回答by Clint

You can declare multi dimensional arrays like :

您可以声明多维数组，如：

// 4 x 5 String arrays, all Strings are null
// [0] -> [null,null,null,null,null]
// [1] -> [null,null,null,null,null]
// [2] -> [null,null,null,null,null]
// [3] -> [null,null,null,null,null]

String[][] sa1 = new String[4][5];
for(int i = 0; i < sa1.length; i++) {           // sa1.length == 4
    for (int j = 0; j < sa1[i].length; j++) {     //sa1[i].length == 5
        sa1[i][j] = "new String value";
    }
}


// 5 x 0  All String arrays are null
// [null]
// [null]
// [null]
// [null]
// [null]
String[][] sa2 = new String[5][];
for(int i = 0; i < sa2.length; i++) {
    String[] anon = new String[ /* your number here */];
    // or String[] anon = new String[]{"I'm", "a", "new", "array"};
    sa2[i] = anon;
}

// [0] -> ["I'm","in","the", "0th", "array"]
// [1] -> ["I'm", "in", "another"]
String[][] sa3 = new String[][]{ {"I'm","in","the", "0th", "array"},{"I'm", "in", "another"}};

回答by A_M

You can also use the following construct:

您还可以使用以下构造：

String[][] myStringArray = new String [][] { { "X0", "Y0"},
                                             { "X1", "Y1"},
                                             { "X2", "Y2"},
                                             { "X3", "Y3"},
                                             { "X4", "Y4"} };

回答by aioobe

Java doesn't have "true" multidimensional arrays.

Java 没有“真正的”多维数组。

For example, arr[i][j][k]is equivalent to ((arr[i])[j])[k]. In other words, arris simply an array, of arrays, of arrays.

例如，arr[i][j][k]相当于((arr[i])[j])[k]。换句话说，arr只是一个数组，数组，数组。

So, if you know how arrays work, you know how multidimensional arrays work!

所以，如果你知道数组是如何工作的，你就会知道多维数组是如何工作的！

---

---

Declaration:

宣言：

int[][][] threeDimArr = new int[4][5][6];

or, with initialization:

或者，初始化：

int[][][] threeDimArr = { { { 1, 2 }, { 3, 4 } }, { { 5, 6 }, { 7, 8 } } };

---

---

Access:

使用权：

int x = threeDimArr[1][0][1];

or

或者

int[][] row = threeDimArr[1];

---

---

String representation:

字符串表示：

Arrays.deepToString(threeDimArr);

yields

产量

"[[[1, 2], [3, 4]], [[5, 6], [7, 8]]]"

Useful articles

有用的文章

• Java: Initializing a multidimensional array
• Java: Matrices and Multidimensional Arrays

• Java：初始化多维数组
• Java：矩阵和多维数组

回答by Vlad

I'll add that if you want to read the dimensions, you can do this:

我要补充一点，如果你想阅读尺寸，你可以这样做：

int[][][] a = new int[4][3][2];

System.out.println(a.length);  // 4
System.out.println(a[0].length); // 3
System.out.println(a[0][0].length); //2

You can also have jagged arrays, where different rows have different lengths, so a[0].length != a[1].length.

您还可以使用锯齿状数组，其中不同的行具有不同的长度，因此a[0].length != a[1].length.

回答by Isabella Engineer

Multidimensional Array in Java

Java中的多维数组

Returning a multidimensional array

返回多维数组

Java does not truelysupport multidimensional arrays. In Java, a two-dimensional array is simply an array of arrays, a three-dimensional array is an array of arrays of arrays, a four-dimensional array is an array of arrays of arrays of arrays, and so on...

Java 并不真正支持多维数组。在Java中，二维数组就是简单的数组数组，三维数组就是数组数组的数组，四维数组就是数组数组的数组，等等……

We can define a two-dimensional array as:

我们可以将二维数组定义为：

1. int[ ] num[ ] = {{1,2}, {1,2}, {1,2}, {1,2}}

2. int[ ][ ] num = new int[4][2]

   num[0][0] = 1;
   num[0][1] = 2;
   num[1][0] = 1;
   num[1][1] = 2;
   num[2][0] = 1;
   num[2][1] = 2;
   num[3][0] = 1;
   num[3][1] = 2;
   

   If you don't allocate, let's say num[2][1], it is not initialized and then it is automatically allocated 0, that is, automatically num[2][1] = 0;

3. Below, num1.lengthgives you rows.

4. While num1[0].lengthgives you the number of elements related to num1[0]. Here num1[0]has related arrays num1[0][0]and num[0][1]only.

5. Here we used a forloop which helps us to calculate num1[i].length. Here iis incremented through a loop.

   class array
   {
       static int[][] add(int[][] num1,int[][] num2)
       {
           int[][] temp = new int[num1.length][num1[0].length];
           for(int i = 0; i<temp.length; i++)
           {
               for(int j = 0; j<temp[i].length; j++)
               {
                   temp[i][j] = num1[i][j]+num2[i][j];
               }
           }
           return temp;
       }
   
       public static void main(String args[])
       {
           /* We can define a two-dimensional array as
                1.  int[] num[] = {{1,2},{1,2},{1,2},{1,2}}
                2.  int[][] num = new int[4][2]
                    num[0][0] = 1;
                    num[0][1] = 2;
                    num[1][0] = 1;
                    num[1][1] = 2;
                    num[2][0] = 1;
                    num[2][1] = 2;
                    num[3][0] = 1;
                    num[3][1] = 2;
   
                    If you don't allocate let's say num[2][1] is
                    not initialized, and then it is automatically
                    allocated 0, that is, automatically num[2][1] = 0;
                 3. Below num1.length gives you rows
                 4. While num1[0].length gives you number of elements
                    related to num1[0]. Here num1[0] has related arrays
                    num1[0][0] and num[0][1] only.
                 5. Here we used a 'for' loop which helps us to calculate
                    num1[i].length, and here i is incremented through a loop.
           */
           int num1[][] = {{1,2},{1,2},{1,2},{1,2}};
           int num2[][] = {{1,2},{1,2},{1,2},{1,2}};
   
           int num3[][] = add(num1,num2);
           for(int i = 0; i<num1.length; i++)
           {
               for(int j = 0; j<num1[j].length; j++)
                   System.out.println("num3[" + i + "][" + j + "]=" + num3[i][j]);
           }
       }
   }
   

1. int[ ] num[ ] = {{1,2}, {1,2}, {1,2}, {1,2}}

2. int[ ][ ] num = new int[4][2]

   num[0][0] = 1;
   num[0][1] = 2;
   num[1][0] = 1;
   num[1][1] = 2;
   num[2][0] = 1;
   num[2][1] = 2;
   num[3][0] = 1;
   num[3][1] = 2;
   

   如果不分配，比方说num[2][1]，不初始化，然后自动分配0，即自动num[2][1] = 0；

3. 下面，num1.length给你行。

4. 虽然num1[0].length为您提供了与num1[0]. 这里num1[0]有相关的数组num1[0][0]并且num[0][1]只有。

5. 这里我们使用了一个for循环来帮助我们计算num1[i].length。这里i是通过循环递增的。

   class array
   {
       static int[][] add(int[][] num1,int[][] num2)
       {
           int[][] temp = new int[num1.length][num1[0].length];
           for(int i = 0; i<temp.length; i++)
           {
               for(int j = 0; j<temp[i].length; j++)
               {
                   temp[i][j] = num1[i][j]+num2[i][j];
               }
           }
           return temp;
       }
   
       public static void main(String args[])
       {
           /* We can define a two-dimensional array as
                1.  int[] num[] = {{1,2},{1,2},{1,2},{1,2}}
                2.  int[][] num = new int[4][2]
                    num[0][0] = 1;
                    num[0][1] = 2;
                    num[1][0] = 1;
                    num[1][1] = 2;
                    num[2][0] = 1;
                    num[2][1] = 2;
                    num[3][0] = 1;
                    num[3][1] = 2;
   
                    If you don't allocate let's say num[2][1] is
                    not initialized, and then it is automatically
                    allocated 0, that is, automatically num[2][1] = 0;
                 3. Below num1.length gives you rows
                 4. While num1[0].length gives you number of elements
                    related to num1[0]. Here num1[0] has related arrays
                    num1[0][0] and num[0][1] only.
                 5. Here we used a 'for' loop which helps us to calculate
                    num1[i].length, and here i is incremented through a loop.
           */
           int num1[][] = {{1,2},{1,2},{1,2},{1,2}};
           int num2[][] = {{1,2},{1,2},{1,2},{1,2}};
   
           int num3[][] = add(num1,num2);
           for(int i = 0; i<num1.length; i++)
           {
               for(int j = 0; j<num1[j].length; j++)
                   System.out.println("num3[" + i + "][" + j + "]=" + num3[i][j]);
           }
       }
   }
   

回答by Ranjit

You can look at this to start off:

你可以看看这个开始：

    int [][][] i = {                //third dimension curly brace
                     {               // second dimension curly brace
                        {            //first dimension curly brace
                           1,1,1    //elements
                        },           
                    {3,3,3},    
                    {2,2,2}     
                      },
                      {
                         {
                          1,1,1
                         },
                         {3,3,3},
                         {2,2,2}
                       }
                    };      

回答by Fridjato Part Fridjat

 int[][] myNums = { {1, 2, 3, 4, 5, 6, 7}, {5, 6, 7, 8, 9, 10, 11} };
 for (int x = 0; x < myNums.length; ++x) {
    for(int y = 0; y < myNums[i].length; ++y) {
       System.out.print(myNums[x][y]);
    }
 }

Output

输出

1 2 3 4 5 6 7 5 6 7 8 9 10 11

1 2 3 4 5 6 7 5 6 7 8 9 10 11