xcode “现在停止发出太多错误” - 如何增加或删除限制？
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"too many errors emitted stopping now" - How to increase or remove the limit?
提问by Erik B
So I'm doing some refactoring and it's really annoying that I don't get all the errors up front. How can I either increase the limit or remove the limit, so that the compiler will output all the errors it can find?
所以我正在做一些重构，而且我没有预先得到所有的错误真的很烦人。如何增加限制或删除限制，以便编译器输出它可以找到的所有错误？
回答by Erik B
So I found how to do it. You add this compiler flag:
所以我找到了怎么做。你添加这个编译器标志：
-ferror-limit=0
0 means that it will not stop because of too many errors.
0 表示不会因为错误太多而停止。
This seems to be a question and answer that explains how to add a compiler flag in Xcode 4:
这似乎是一个问答，解释了如何在 Xcode 4 中添加编译器标志：
回答by James O'Brien
Maybe this:
也许这个：
Preferences > General > Continue Building After Errors
首选项 > 常规 > 出错后继续构建
https://developer.apple.com/library/ios/recipes/xcode_help-general_preferences/Recipe.html
https://developer.apple.com/library/ios/recipes/xcode_help-general_preferences/Recipe.html
回答by John Nash
Here is the complete syntax to compile and pass the flags to the make command
这是编译并将标志传递给 make 命令的完整语法
make install CFLAGS="-ferror-limit=0"
使安装 CFLAGS="-ferror-limit=0"
Also as outlined here: https://developer.apple.com/library/content/documentation/Porting/Conceptual/PortingUnix/compiling/compiling.html
也如此处所述：https: //developer.apple.com/library/content/documentation/Porting/Conceptual/PortingUnix/compiling/compiling.html
