Javascript 在javascript中搜索和替换特定的查询字符串参数值

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时间:2020-08-23 17:05:52  来源:igfitidea点击:

Search and replace specific query string parameter value in javascript

javascriptsearchreplacedesign-patternsmatch

提问by TopCoder

I have a string which is something like this :

我有一个像这样的字符串:

a_href= "www.google.com/test_ref=abc";

I need to search for test_ref=abc in thisabove strinng and replace it with new value

我需要在上面的字符串中搜索 test_ref=abc 并将其替换为新值

var updated_test_ref = "xyz";

a_href ="www.google.com/test_ref=updated_test_ref" 

i.e

IE

www.google.com/test_ref=xyz.

How can we do this ?

我们应该怎么做 ?

EDIT:

编辑:

test_ref value can be a URL link in itself something like http://google.com?param1=test1&param2=test2. I need to capture complete value not till first &.

test_ref 值本身可以是一个 URL 链接,例如http://google.com?param1=test1¶m2=test2。我需要在第一个 & 之前捕获完整的价值。

回答by Mark Kahn

a_href = a_href.replace(/(test_ref=)[^\&]+/, '' + updated_test_ref);

回答by Nejc Lepen

Based on this discussion I have fixed the Chris function (problem with regex string!)

基于此讨论,我修复了 Chris 函数(正则表达式字符串的问题!)

function updateUrlParameter(url, param, value){
    var regex = new RegExp('('+param+'=)[^\&]+');
    return url.replace( regex , '' + value);
}

回答by Chris

Based on this discussion I have created a references function. enjoy

基于这个讨论,我创建了一个引用函数。请享用

updateUrlParameter(url, param, value){
    var regex = new RegExp("/([?|&]" + param + "=)[^\&]+/");
    return url.replace(regex, '' + value);
}

回答by souravb

I was searching for this solution for few hours and finally stumbled upon this question. I have tried all the solutions here. But there is still an issue while replacing specific param value in url. Lets take a sample url like

我一直在寻找这个解决方案几个小时,最后偶然发现了这个问题。我已经尝试了这里的所有解决方案。但是在替换 url 中的特定参数值时仍然存在问题。让我们以一个示例网址为例

http://google.com?param1=test1&param2=test2&anotherparam1=test3

http://google.com?param1=test1&param2=test2&anotherparam1=test3

and the updated url should be like

更新后的网址应该是这样的

http://google.com?param1=newtest&param2=test2&anotherparam1=test3, where value of param1is changed.

http://google.com?param1=newtest&param2=test2&anotherparam1=test3,其中的值param1发生了变化。

In this case, as @Panthrohas pointed out, adding [?|&]before the querying string ensures that anotherparam1is not replaced. But this solution also adds the '?' or '&' character to the matching string. So while replacing the matched characters, the '?' or '&' will also get replaced. You will not know exactly which character is replaced so you cannot append that character as well.

在这种情况下,正如@ Panthro指出的那样,[?|&]在查询字符串之前添加可确保anotherparam1不会被替换。但是这个解决方案还添加了“?” 或 '&' 字符到匹配的字符串。因此,在替换匹配的字符时,'?' 或 '&' 也将被替换。您不会确切知道替换了哪个字符,因此您也无法附加该字符。

The solution is to match '?' or '&' as preceding characters only.

解决方案是匹配“?” 或 '&' 仅作为前面的字符。

I have re-written the function of @Chris, fixing the issue with string and have added case insensitive argument.

我已经重新编写的@功能克里斯,固定用绳子的问题,并增加了不区分大小写的说法。

updateUrlParameter(url, param, value){
    var regex = new RegExp('(?<=[?|&])(' + param + '=)[^\&]+', 'i');
    // return url.replace(regex, param + '=' + value);
    return url.replace(regex, param + '=' + value);
}

Here (?<=[?|&])means, the regex will match '?' or '&' char and will take the string that occurs after the specified character (looks behind the character). That means only param1=test1substring will be matched and replaced.

这里的(?<=[?|&])意思是,正则表达式将匹配 '?' 或 '&' char 并将采用出现在指定字符之后的字符串(在字符后面)。这意味着只会param1=test1匹配和替换子字符串。

回答by Roni Tovi

I know this is a bit dirty code but I've achieved what I was looking for. It replaces the given query string or adds new one if it doesn't exist yet.

我知道这是一个有点脏的代码,但我已经实现了我想要的。它替换给定的查询字符串或添加新的(如果尚不存在)。

function updateUrlParameter(url, param, value) {

    var index = url.indexOf("?");

    if (index > 0) {

        var u = url.substring(index + 1).split("&");

        var params = new Array(u.length);

        var p;
        var found = false;

        for (var i = 0; i < u.length; i++) {
            params[i] = u[i].split("=");
            if (params[i][0] === param) {
                params[i][1] = value;
                found = true;
            }
        }

        if (!found) {
            params.push(new Array(2));
            params[params.length - 1][0] = param;
            params[params.length - 1][1] = value;
        }

        var res = url.substring(0, index + 1) + params[0][0] + "=" + params[0][1];
        for (var i = 1; i < params.length; i++) {
            res += "&" + params[i][0] + "=" + params[i][1];
        }
        return res;

    } else {
        return url + "?" + param + "=" + value;
    }

}

It will work when given regular URL addresses like:

当给定常规 URL 地址时,它将起作用,例如:

updateUrlParameter('https://www.example.com/some.aspx?mid=1&id=2','id','5');
updateUrlParameter('https://www.example.com/?mid=1&id=2','id','5');
updateUrlParameter('https://www.example.com/some.aspx','id','5');

Please noteIt will NOT work only if any of the query string parameter name or value contains "=" and/or "&" chars. It will work just fine behind that.

请注意,仅当任何查询字符串参数名称或值包含“=”和/或“&”字符时,它才会起作用。在这之后它会工作得很好。

回答by Mohamed.Abdo

*Java script code to find a specific query string and replace its value *

*用于查找特定查询字符串并替换其值的 Java 脚本代码 *

('input.letter').click(function () {
                //0- prepare values
                var qsTargeted = 'letter=' + this.value; //"letter=A";
                var windowUrl = '';
                var qskey = qsTargeted.split('=')[0];
                var qsvalue = qsTargeted.split('=')[1];
                //1- get row url
                var originalURL = window.location.href;
                //2- get query string part, and url
                if (originalURL.split('?').length > 1) //qs is exists
                {
                    windowUrl = originalURL.split('?')[0];
                    var qs = originalURL.split('?')[1];
                    //3- get list of query strings
                    var qsArray = qs.split('&');
                    var flag = false;
                    //4- try to find query string key
                    for (var i = 0; i < qsArray.length; i++) {
                        if (qsArray[i].split('=').length > 0) {
                            if (qskey == qsArray[i].split('=')[0]) {
                                //exists key
                                qsArray[i] = qskey + '=' + qsvalue;
                                flag = true;
                                break;
                            }
                        }
                    }
                    if (!flag)//   //5- if exists modify,else add
                    {
                        qsArray.push(qsTargeted);
                    }
                    var finalQs = qsArray.join('&');
                    //6- prepare final url
                    window.location = windowUrl + '?' + finalQs;
                }
                else {
                    //6- prepare final url
                    //add query string
                    window.location = originalURL + '?' + qsTargeted;
                }
            })
        });