PHP file_get_contents() 返回“无法打开流：HTTP 请求失败！”
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PHP file_get_contents() returns "failed to open stream: HTTP request failed!"
提问by undefined
I am having problems calling a url from PHP code. I need to call a service using a query string from my PHP code. If I type the url into a browser, it works ok, but if I use file-get-contents() to make the call, I get:
我在从 PHP 代码调用 url 时遇到问题。我需要使用 PHP 代码中的查询字符串调用服务。如果我在浏览器中输入 url，它工作正常，但如果我使用 file-get-contents() 进行调用，我得到：
Warning: file-get-contents(http://.... ) failed to open stream: HTTP request failed! HTTP/1.1 202 Accepted in ...
警告：file-get-contents(http://....) 无法打开流：HTTP 请求失败！HTTP/1.1 202 接受...
The code I am using is:
我正在使用的代码是：
$query=file_get_contents('http://###.##.##.##/mp/get?mpsrc=http://mybucket.s3.amazonaws.com/11111.mpg&mpaction=convert format=flv');
echo($query);
Like I said - call from the browser and it works fine. Any suggestions?
就像我说的 - 从浏览器调用，它工作正常。有什么建议？
I have also tried with another url such as:
我也尝试过另一个网址，例如：
$query=file_get_contents('http://www.youtube.com/watch?v=XiFrfeJ8dKM');
This works fine... could it be that the url I need to call has a second http://in it?
这工作正常......可能是我需要调用的网址中有第二个http://吗？
回答by James Hall
Try using cURL.
尝试使用卷曲。
<?php
$curl_handle=curl_init();
curl_setopt($curl_handle, CURLOPT_URL,'http://###.##.##.##/mp/get?mpsrc=http://mybucket.s3.amazonaws.com/11111.mpg&mpaction=convert format=flv');
curl_setopt($curl_handle, CURLOPT_CONNECTTIMEOUT, 2);
curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($curl_handle, CURLOPT_USERAGENT, 'Your application name');
$query = curl_exec($curl_handle);
curl_close($curl_handle);
?>
回答by SilentGhost
回答by pangeli
<?php
$lurl=get_fcontent("http://ip2.cc/?api=cname&ip=84.228.229.81");
echo"cid:".$lurl[0]."<BR>";
function get_fcontent( $url, $javascript_loop = 0, $timeout = 5 ) {
$url = str_replace( "&", "&", urldecode(trim($url)) );
$cookie = tempnam ("/tmp", "CURLCOOKIE");
$ch = curl_init();
curl_setopt( $ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; rv:1.7.3) Gecko/20041001 Firefox/0.10.1" );
curl_setopt( $ch, CURLOPT_URL, $url );
curl_setopt( $ch, CURLOPT_COOKIEJAR, $cookie );
curl_setopt( $ch, CURLOPT_FOLLOWLOCATION, true );
curl_setopt( $ch, CURLOPT_ENCODING, "" );
curl_setopt( $ch, CURLOPT_RETURNTRANSFER, true );
curl_setopt( $ch, CURLOPT_AUTOREFERER, true );
curl_setopt( $ch, CURLOPT_SSL_VERIFYPEER, false ); # required for https urls
curl_setopt( $ch, CURLOPT_CONNECTTIMEOUT, $timeout );
curl_setopt( $ch, CURLOPT_TIMEOUT, $timeout );
curl_setopt( $ch, CURLOPT_MAXREDIRS, 10 );
$content = curl_exec( $ch );
$response = curl_getinfo( $ch );
curl_close ( $ch );
if ($response['http_code'] == 301 || $response['http_code'] == 302) {
ini_set("user_agent", "Mozilla/5.0 (Windows; U; Windows NT 5.1; rv:1.7.3) Gecko/20041001 Firefox/0.10.1");
if ( $headers = get_headers($response['url']) ) {
foreach( $headers as $value ) {
if ( substr( strtolower($value), 0, 9 ) == "location:" )
return get_url( trim( substr( $value, 9, strlen($value) ) ) );
}
}
}
if ( ( preg_match("/>[[:space:]]+window\.location\.replace\('(.*)'\)/i", $content, $value) || preg_match("/>[[:space:]]+window\.location\=\"(.*)\"/i", $content, $value) ) && $javascript_loop < 5) {
return get_url( $value[1], $javascript_loop+1 );
} else {
return array( $content, $response );
}
}
?>
回答by Michael Wales
file_get_contents()utilizes the fopen()wrappers, therefore it is restricted from accessing URLs through the allow_url_fopenoption within php.ini.
file_get_contents()使用fopen()包装器，因此它被限制通过allow_url_fopenphp.ini 中的选项访问 URL 。
You will either need to alter your php.ini to turn this option on or use an alternative method, namely cURL- by far the most popular and, to be honest, standard way to accomplish what you are trying to do.
您要么需要更改 php.ini 以打开此选项，要么使用替代方法，即cURL- 迄今为止最流行的，老实说，是完成您要执行的操作的标准方法。
回答by d_bhatnagar
You basically are required to send some information with the request.
您基本上需要随请求发送一些信息。
Try this,
尝试这个，
$opts = array('http'=>array('header' => "User-Agent:MyAgent/1.0\r\n"));
//Basically adding headers to the request
$context = stream_context_create($opts);
$html = file_get_contents($url,false,$context);
$html = htmlspecialchars($html);
This worked out for me
这对我有用
回答by slim
I notice that your URL has spaces in it. I think that usually is a bad thing. Try encoding the URL with
我注意到您的网址中有空格。我认为这通常是一件坏事。尝试对 URL 进行编码
$my_url = urlencode("my url");
and then calling
然后打电话
file_get_contents($my_url);
and see if you have better luck.
看看你是否有更好的运气。
回答by Emre Karata?o?lu
I got a similar problem , I parsed the youtube url. The code is;
我遇到了类似的问题，我解析了 youtube 网址。代码是;
$json_is = "http://gdata.youtube.com/feeds/api/videos?q=".$this->video_url."&max-results=1&alt=json";
$video_info = json_decode ( file_get_contents ( $json_is ), true );
$video_title = is_array ( $video_info ) ? $video_info ['feed'] ['entry'] [0] ['title'] ['$t'] : '';
Then I realise that $this->video_urlinclude the whitespace. I solved that using trim($this->video_url).
然后我意识到$this->video_url包括空格。我使用trim($this->video_url).
Maybe it will help you . Good Luck
也许它会帮助你。祝你好运
回答by alexn
I'm not sure about the parameters(mpaction, format), if they are specified for the amazonaws page or ##.##.
我不确定参数（mpaction、格式），如果它们是为 amazonaws 页面或 ##.## 指定的。
Try to urlencode()the url.
尝试urlencode()url。
回答by Sergey
$query=file_get_contents('http://###.##.##.##/mp/get?' . http_build_query(array('mpsrc' => 'http://mybucket.s3.amazonaws.com/11111.mpg&mpaction=convert format=flv')));
回答by Jerry
I got a similar problem.
我遇到了类似的问题。
Due to timeout !
由于超时！
Timeout can be indicated like this :
超时可以这样表示：
$options = array(
'http' => array(
'header' => "Content-type: application/x-www-form-urlencoded\r\n",
'method' => "POST",
'content' => http_build_query($data2),
'timeout' => 30,
),
);
$context = stream_context_create($options); $retour =
$retour = @file_get_contents("http://xxxxx.xxx/xxxx", false, $context);
