javascript javascript中的正则表达式匹配
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Regular Expression match in javascript
提问by Jaison Justus
I have the string SUM([A2:A10],[B2:B10],[C2:C10],[D2:D10])and I need to get the elements [A2:A10],[B2:B10],[C2:C10],[D2:D10]in an array, so I used match()in js. The code snippet is
我有字符串SUM([A2:A10],[B2:B10],[C2:C10],[D2:D10])，我需要获取[A2:A10],[B2:B10],[C2:C10],[D2:D10]数组中的元素，所以我match()在js中使用。代码片段是
var formula = "SUM([A2:A10],[B2:B10],[C2:C10],[D2:D10])";
var reg = /\[(a-zA-Z0-9)+\]/;
matches = formula.match(reg);
But I am not getting the match. I hope the regular expression is wrong. I am very poor in building regular expression. What will be the correct regular expression?
但我没有得到比赛。我希望正则表达式是错误的。我在构建正则表达式方面很差。什么是正确的正则表达式？
回答by Another Code
Try it like this:
像这样尝试：
var formula = 'SUM([A2:A10],[B2:B10],[C2:C10],[D2:D10])';
var reg = /\[\w+:\w+\]/g;
matches = formula.match(reg);
Output:
输出：
["[A2:A10]", "[B2:B10]", "[C2:C10]", "[D2:D10]"]
Your regex was in the right direction, but didn't include the colon and captured individual characters. The \wescape sequence I used is a shortcut for a word character ([a-zA-Z0-9_]), makes it more readable. The gflag is necessary to get all matches instead of just the first one.
您的正则表达式方向正确，但不包括冒号和捕获的单个字符。\w我使用的转义序列是单词字符 ( [a-zA-Z0-9_])的快捷方式，使其更具可读性。该g标志是获取所有匹配项而不是第一个匹配项所必需的。
回答by jfriend00
var str = "SUM([A2:A10],[B2:B10],[C2:C10],[D2:D10])";
var matches = str.match(/\[[A-Z0-9:]+\]/g);
alert(matches);?
Note, you use the gflag on the regex to get all the matches.
请注意，您使用g正则表达式上的标志来获取所有匹配项。
You can see it working here: http://jsfiddle.net/jfriend00/aTrLU/
你可以在这里看到它的工作：http: //jsfiddle.net/jfriend00/aTrLU/
回答by Chetter Hummin
The regex you need is
您需要的正则表达式是
/\[[A-Z][0-9]+:[A-Z][0-9]+\]/gi
The g modifier indicates that we should do a global mtching and return all the results, not just the first
g 修饰符表示我们应该进行全局匹配并返回所有结果，而不仅仅是第一个
The i modifier indicates that we need a case-insensitive matching
i 修饰符表示我们需要不区分大小写的匹配
An assumption made is that you don't want to include [E2:E10:], because of extra semicolon
所做的假设是您不想包含 [E2:E10:]，因为有额外的分号
回答by Diode
var formula = "SUM([A2:A10],[B2:B10],[C2:C10],[D2:D10])";
var reg = /\[.*?\]/g;
matches = formula.match(reg);
回答by Has QUIT--Anony-Mousse
Your regexp doesn't include the colon :.
您的正则表达式不包括冒号:。
Try this: /\[([0-9A-Z:]+)\]/, in particular why I have quoted and unquoted square brackets there.
试试这个: /\[([0-9A-Z:]+)\]/，特别是为什么我在那里引用了和未引用的方括号。
Plus, your input string isn't quoted.
另外，您的输入字符串没有被引用。
回答by ZER0
I believe you forgot the quotes. Also, what you need is also the global flag. Here the code:
我相信你忘记了引号。此外，您还需要全局标志。这里的代码：
var formula = "SUM([A2:A10],[B2:B10],[C2:C10],[D2:D10])";
var reg = /\[[0-z]+:[0-z]+\]/g;
var matches = formula.match(reg);
