Python 将 unix 时间戳字符串转换为可读日期
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Converting unix timestamp string to readable date
提问by VeryNewToPython
I have a string representing a unix timestamp (i.e. "1284101485") in Python, and I'd like to convert it to a readable date. When I use time.strftime, I get a TypeError:
我有一个字符串表示 Python 中的 unix 时间戳（即“1284101485”），我想将其转换为可读日期。当我使用时time.strftime，我得到一个TypeError：
>>>import time
>>>print time.strftime("%B %d %Y", "1284101485")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: argument must be 9-item sequence, not str
回答by Daniel
>>> from datetime import datetime
>>> datetime.fromtimestamp(1172969203.1)
datetime.datetime(2007, 3, 4, 0, 46, 43, 100000)
Taken from http://seehuhn.de/pages/pdate
回答by Micha? Niklas
Use datetimemodule:
使用datetime模块：
from datetime import datetime
ts = int("1284101485")
# if you encounter a "year is out of range" error the timestamp
# may be in milliseconds, try `ts /= 1000` in that case
print(datetime.utcfromtimestamp(ts).strftime('%Y-%m-%d %H:%M:%S'))
回答by John La Rooy
>>> import time
>>> time.ctime(int("1284101485"))
'Fri Sep 10 16:51:25 2010'
>>> time.strftime("%D %H:%M", time.localtime(int("1284101485")))
'09/10/10 16:51'
回答by Nick
You can convert the current time like this
您可以像这样转换当前时间
t=datetime.fromtimestamp(time.time())
t.strftime('%Y-%m-%d')
'2012-03-07'
To convert a date in string to different formats.
将字符串中的日期转换为不同的格式。
import datetime,time
def createDateObject(str_date,strFormat="%Y-%m-%d"):
timeStamp = time.mktime(time.strptime(str_date,strFormat))
return datetime.datetime.fromtimestamp(timeStamp)
def FormatDate(objectDate,strFormat="%Y-%m-%d"):
return objectDate.strftime(strFormat)
Usage
=====
o=createDateObject('2013-03-03')
print FormatDate(o,'%d-%m-%Y')
Output 03-03-2013
回答by Jared Burrows
For a human readable timestamp from a UNIX timestamp, I have used this in scripts before:
对于来自 UNIX 时间戳的人类可读时间戳，我之前在脚本中使用过它：
import os, datetime
datetime.datetime.fromtimestamp(float(os.path.getmtime("FILE"))).strftime("%B %d, %Y")
Output:
输出：
'December 26, 2012'
'2012 年 12 月 26 日'
回答by eqzx
quick and dirty one liner:
快速和肮脏的一个班轮：
'-'.join(str(x) for x in list(tuple(datetime.datetime.now().timetuple())[:6]))
'2013-5-5-1-9-43'
'2013-5-5-1-9-43'
回答by itsaruns
import datetime
temp = datetime.datetime.fromtimestamp(1386181800).strftime('%Y-%m-%d %H:%M:%S')
print temp
回答by nimmy
i just successfully used:
我刚刚成功使用：
>>> type(tstamp)
pandas.tslib.Timestamp
>>> newDt = tstamp.date()
>>> type(newDt)
datetime.date
回答by Raphael Amoedo
回答by rkachach
The most voted answer suggests using fromtimestamp which is error prone since it uses the local timezone. To avoid issues a better approach is to use UTC:
投票最多的答案建议使用 fromtimestamp ，这很容易出错，因为它使用本地时区。为了避免问题，更好的方法是使用 UTC：
datetime.datetime.utcfromtimestamp(posix_time).strftime('%Y-%m-%dT%H:%M:%SZ')
Where posix_time is the Posix epoch time you want to convert
其中 posix_time 是您要转换的 Posix 纪元时间
