C++ 如何获取当前日期和时间？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/8343676/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
提示：将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间：2020-08-28 18:24:12 来源:igfitidea点击:
How to get current date and time?
提问by Wizard
How to get current date d/m/y. I need that they have 3 different variables not one, for example day=d; month=m; year=y;.
如何获取当前日期 d/m/y。我需要他们有 3 个不同的变量而不是一个，例如day=d; month=m; year=y;.
回答by Petesh
For linux, you would use the 'localtime'function.
对于 linux，您将使用'localtime'函数。
#include <time.h>
time_t theTime = time(NULL);
struct tm *aTime = localtime(&theTime);
int day = aTime->tm_mday;
int month = aTime->tm_mon + 1; // Month is 0 - 11, add 1 to get a jan-dec 1-12 concept
int year = aTime->tm_year + 1900; // Year is # years since 1900
回答by sehe
Here is the chronoway (C++0x) - see it live on http://ideone.com/yFm9P
这是chrono方式 (C++0x) - 在http://ideone.com/yFm9P 上实时查看
#include <chrono>
#include <ctime>
#include <iostream>
using namespace std;
typedef std::chrono::system_clock Clock;
int main()
{
auto now = Clock::now();
std::time_t now_c = Clock::to_time_t(now);
struct tm *parts = std::localtime(&now_c);
std::cout << 1900 + parts->tm_year << std::endl;
std::cout << 1 + parts->tm_mon << std::endl;
std::cout << parts->tm_mday << std::endl;
return 0;
}
