javascript 从 get 方法中删除 %20 值
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Removing %20 value from get method
提问by Smitha
Removing %20 in get method?
在 get 方法中删除 %20？
var c=new Array(a);
(eg: a={"1","2"}) window.location="my_details.html?"+ c + "_";
and in my_details.html :
在 my_details.html 中：
var q=window.location.search;
alert("qqqqqqqqqqqqq " + q);
var arrayList = (q)? q.substring(1).split("_"):[];
var list=new Array(arrayList);
alert("dataaaaaaaaaaaa " + list + "llll " );
and in "list" its dusplaying me "1%202";
在“列表”中，它在欺骗我"1%202"；
How can I remove this %20 =spacevalue ??
我怎样才能删除这个%20 =space值？
Thanks
谢谢
回答by evildead
just use this:
只需使用这个：
alert("dataaaaaaaaaaaa " + decodeURIComponent(list) + "llll " );
This should decode the %20to space
这应该解码%20到space
look here: http://www.w3schools.com/jsref/jsref_decodeURIComponent.asp
看这里：http: //www.w3schools.com/jsref/jsref_decodeURIComponent.asp
回答by st0le
If there is a space in the parameter(s), then the %20(URL Encoding) is necessary. You cannot pass a space in a GETrequest.
如果参数中有空格，则%20(URL Encoding) 是必需的。您不能在GET请求中传递空格。
If you need to avoid this, use POST.
如果您需要避免这种情况，请使用POST.
回答by jabclab
As far as I can see the problem is being introduced at this line:
据我所知，问题是在这一行引入的：
window.location="my_details.html?"+ c + "_";
This could be written as:
这可以写成：
window.location="my_details.html?"+ c.toString() + "_";
The default.toString()of a JavaScript Arraywould be to use a delimiter of ,, i.e.
JavaScript的默认值是使用 的分隔符，即.toString()Array,
var str = ["1", "2", "3"].toString(); // 1,2,3
In you example it appears that the delimiter being used is a space. This would have been changed by something changing the default behaviour of .toString()on the Array.prototype. Try using the following:
在您的示例中，使用的分隔符似乎是一个空格。这已被一些改变的默认行为改变.toString()的Array.prototype。尝试使用以下方法：
window.location="my_details.html?"+ c.join(",") + "_";
回答by satya
Better to use replace() method to replace %20to space
最好使用 replace() 方法替换%20为space
list.replace("%20"," ");
list.replace("%20"," ");
