C语言 C: 0x11 十进制
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C: 0x11 in Decimal
提问by Yonatan
Sorry about this basic question, but why 0x11is 17in decimal (print(%d, 0x11)=17?
抱歉这个基本问题，但为什么0x11是17十进制(print(%d, 0x11)=17？
I search information about the way to convert from hex to dec, but it doesn't talk about this sort of numbers.
我搜索有关从十六进制转换为十进制的方法的信息，但它没有谈论这种数字。
回答by codekaizen
Just like "11" in base ten means "1 ten" and "1 one", "11" in base 16 (i.e. hex) means "1 sixteen" and "1 one" - or 17 in base 10.
就像基数 10 中的“11”表示“1 十”和“1 一”一样，基数 16（即十六进制）中的“11”表示“16”和“1 一” - 或基数 17 中的 17。
回答by patapizza
0x11 = 1*16^1 + 1*16^0 = 17. (Like 17 = 1 * 10^1 + 7 * 10^0.)
0x11 = 1*16^1 + 1*16^0 = 17。（比如 17 = 1 * 10^1 + 7 * 10^0。）
回答by geofftnz
0xat the start of a number means that the compiler will read it as hexadecimal. 0x11= 1 * 16 + 1 = 17
0x在数字的开头意味着编译器会将其读取为十六进制。0x11=1 * 16 + 1 = 17
回答by maerics
0x11 = 1 * 16^1 (16)
+ 1 * 16^0 ( 1)
-----------------
0x11 (17)
Just like:
就像：
17 = 1 * 10^1 (10)
+ 7 * 10^0 ( 7)
-----------------
17 (17)
回答by kevinji
Hexadecimal counts with 16 digits, instead of 10. To account for the extra 6 digits, it uses letters Ato F.
十六进制计数为 16 位，而不是 10。为了说明额外的 6 位，它使用字母A到F。
Counting from 0 in both base 16 and base 10:
以 16 和 10 为基数从 0 开始计数：
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F, 10, 11 (base 16)
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17 (base 10)
Also, to convert from base 16 to base 10:
此外，要从基数 16 转换为基数 10：
1116= 1 * 16 + 1 = 1710
11 16= 1 * 16 + 1 = 17 10
回答by Vinicius Kamakura
Well, maybe because 0x11 IS17 in decimal?
好吧，也许是因为 0x11是十进制的 17？
回答by Paul Sullivan
here is an easy way of seeing
这是一个简单的观看方式
128 64 32 16 8 4 2 1 = Decimal values of the...
0 0 0 1 0 0 0 1 = Boolean switches that are ON or OFF
128 64 32 16 8 4 2 1 = 十进制值...
0 0 0 1 0 0 0 1 = 打开或关闭的布尔开关
add them together 16 + 1 = 17
将它们加在一起 16 + 1 = 17
