如何在 Java 中一次性从整个字符串中转义所有特殊字符
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How to escape all Special Characters from whole string at one go in Java
提问by gozizibj
Lucene supports escaping special characters that are part of the query syntax. The current list special characters are
Lucene 支持转义作为查询语法一部分的特殊字符。当前列表特殊字符是
+ - && || ! ( ) { } [ ] ^ " ~ * ? : \
To escape these character use the \ before the character. For example to search for (1+1):2 use the query:
要转义这些字符，请在字符前使用 \。例如要搜索 (1+1):2 使用查询：
\(1\+1\)\:2
My question is how to escape from whole string at one go?For example myStringToEscape = "ABC^ " ~ * ? :DEF";How to get a escapedString.
我的问题是如何一次从整个字符串中逃脱？例如myStringToEscape = "ABC^ " ~ * ? :DEF";如何获得一个escapedString。
回答by femtoRgon
You can use QueryParser.escape, such as:
您可以使用QueryParser.escape，例如：
String escapedString = queryParser.escape(searchString);
queryParser.parse("field:" + escapedString);
回答by ADDruid
If you are just looking for simple replacement, this will do the trick.
如果您只是在寻找简单的替代品，这可以解决问题。
String regex = "([+\-!\(\){}\[\]^\"~*?:\\]|[&\|]{2})";
String myStringToEscape = "ABC^ \" ~ * ? :DEF";
String myEscapedString = myStringToEscape.replaceAll(regex, "\\");
System.out.println(myEscapedString);
This will output:
这将输出：
ABC\^ \" \~ \* \? \:DEF
