如何使用小于和大于 javascript 的条件删除数组值
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How to remove array values using condition less than and greater than in javascript
提问by divakar
I want to remove values from using less than and greater than condition for example my array is
我想从使用小于和大于条件中删除值，例如我的数组是
138,124,128,126,140,113,102,128,136,110,134,132,130,132,132,104,116,135,120
so now my minimum value is 120 and maximum value is 130. I want to remove all the remaining elements from the array. Is this possible in javascript.
所以现在我的最小值是 120，最大值是 130。我想从数组中删除所有剩余的元素。这在javascript中可能吗？
I am newbie so any help would be appreciated.
我是新手，所以任何帮助将不胜感激。
回答by adeneo
回答by Mr. Polywhirl
Just going to extend on the filter and throw it into a reusable function:
只是要扩展过滤器并将其放入可重用的函数中：
var arr = [
138,124,128,126,140,113,102,128,136,110,134,132,130,132,132,104,116,135,120
]
/*
* @param arr Array of integers
* @param min Minimum (Inclusive)
* @param max Maximum (Exclusive)
*/
var filterInRange = function(arr, min, max) {
return arr.filter(function(item) {
return item >= min && item < max;
});
}
console.log(filterInRange(arr, 120, 131).sort()); // [120,124,126,128,128,130]
回答by Alireza
Simply use filter, it's created for things like this, the code below should do the job as you want:
简单地使用过滤器，它是为这样的事情创建的，下面的代码应该按照你的意愿完成工作：
//ES6
var arr = [138,124,128,126,140,113,102,128,136,110,134,132,130,132,132,104,116,135,120];
var filteredArr = arr.filter(n => n>120 && n<130); //[124, 128, 126, 128]
回答by ben rudgers
Use the array.prototype.filter()method to return a new array containing only those elements passing a Boolean test.
使用该array.prototype.filter()方法返回一个新数组，该数组仅包含通过布尔测试的那些元素。
function isBigEnough(element) {
return element >= 10; }
var filtered = [12, 5, 8, 130, 44].filter(isBigEnough);
Returns a new array [12, 130, 44].
返回一个新数组[12, 130, 44]。
Along with array.prototype.map()and array.prototype.reduce()array.prototype.filter()facilitates using a functional programming style in JavaScript.
与array.prototype.map()并促进在 JavaScript 中使用函数式编程风格。array.prototype.reduce()array.prototype.filter()
