typescript 如何在不使用对象引用的情况下比较 Angular 中的两个对象
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How to compare two objects in Angular not using reference of object
提问by Karuna Dande
how typescript comparing two objects?
originaltraits:{
artistic:25,
athletic:24,
goodLooks:70,
happiness:0,
health:81
}
newtraits:{
artistic:25,
athletic:24,
goodLooks:70,
happiness:0,
health:81
}
I have these two objects I want to compare these objects' fields not using object reference in Angular then how to compare?
我有这两个对象我想比较这些对象的字段而不使用 Angular 中的对象引用，那么如何比较？
采纳答案by José Quinto Zamora
If you need to do more comparisons like this one on your project, I highly recommend you using library like deep-equal:
如果你需要在你的项目中做更多这样的比较，我强烈建议你使用像 deep-equal 这样的库：
https://www.npmjs.com/package/deep-equal
https://www.npmjs.com/package/deep-equal
It has their types to be used with TypeScript:
它具有可与 TypeScript 一起使用的类型：
回答by Ricardo D. Ferrancullo III
You can compare objects using JSON.stringify(), assuming you have the same order of object properties. i.e:
您可以使用 JSON.stringify() 比较对象，假设您具有相同顺序的对象属性。IE：
JSON.stringify(obj1).toLowerCase() === JSON.stringify(obj2).toLowerCase();
