Java：拆分后获取最后一个元素
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Java: Get last element after split
提问by n00ki3
I am using the String split method and I want to have the last element. The size of the Array can change.
我正在使用 String split 方法，我想要最后一个元素。数组的大小可以改变。
Example:
例子：
String one = "Düsseldorf - Zentrum - Günnewig Uebachs"
String two = "Düsseldorf - Madison"
I want to split the above Strings and get the last item:
我想拆分上述字符串并获取最后一项：
lastone = one.split("-")[here the last item] // <- how?
lasttwo = two.split("-")[here the last item] // <- how?
I don't know the sizes of the arrays at runtime :(
我不知道运行时数组的大小:(
采纳答案by Jon Skeet
Save the array in a local variable and use the array's lengthfield to find its length. Subtract one to account for it being 0-based:
将数组保存在局部变量中并使用数组的length字段来查找其长度。减去 1 以说明它是基于 0 的：
String[] bits = one.split("-");
String lastOne = bits[bits.length-1];
Caveat emptor: if the original string is composed of only the separator, for example "-"or "---", bits.lengthwill be 0 and this will throw an ArrayIndexOutOfBoundsException. Example: https://onlinegdb.com/r1M-TJkZ8
警告 emptor：如果原始字符串仅由分隔符组成，例如"-"or "---"，bits.length将为 0，这将抛出 ArrayIndexOutOfBoundsException。示例：https: //onlinegdb.com/r1M-TJkZ8
回答by Sean A.O. Harney
You mean you don't know the sizes of the arrays at compile-time? At run-time they could be found by the value of lastone.lengthand lastwo.length.
你的意思是你在编译时不知道数组的大小？在运行时，他们可以通过价值发现lastone.length和lastwo.length。
回答by Denis Bazhenov
Or you could use lastIndexOf()method on String
或者你可以lastIndexOf()在 String 上使用方法
String last = string.substring(string.lastIndexOf('-') + 1);
回答by dfa
using a simple, yet generic, helper method like this:
使用一个简单但通用的辅助方法，如下所示：
public static <T> T last(T[] array) {
return array[array.length - 1];
}
you can rewrite:
你可以重写：
lastone = one.split("-")[..];
as:
作为：
lastone = last(one.split("-"));
回答by azerafati
Since he was asking to do it all in the same line using split so i suggest this:
由于他要求使用 split 在同一行中完成所有操作，因此我建议这样做：
lastone = one.split("-")[(one.split("-")).length -1]
I always avoid defining new variables as far as I can, and I find it a very good practice
我总是尽量避免定义新变量，我发现这是一个很好的做法
回答by Jawad Zeb
String str = "www.anywebsite.com/folder/subfolder/directory";
int index = str.lastIndexOf('/');
String lastString = str.substring(index +1);
Now lastStringhas the value "directory"
现在lastString有了价值"directory"
回答by palacsint
回答by Ranosama
You can use the StringUtilsclass in Apache Commons:
您可以在 Apache Commons 中使用StringUtils类：
StringUtils.substringAfterLast(one, "-");
回答by irJvV
I guess you want to do this in i line. It is possible (a bit of juggling though =^)
我猜您想在 i 行中执行此操作。这是可能的（虽然有点杂耍=^）
new StringBuilder(new StringBuilder("Düsseldorf - Zentrum - Günnewig Uebachs").reverse().toString().split(" - ")[0]).reverse()
tadaa, one line -> the result you want (if you split on " - " (space minus space) instead of only "-" (minus) you will loose the annoying space before the partition too =^) so "Günnewig Uebachs" instead of " Günnewig Uebachs" (with a space as first character)
tadaa，一行 -> 你想要的结果（如果你在“ - ”（空格减去空格）而不是仅“ - ”（减去）上拆分，你也会在分区之前失去烦人的空间=^）所以“Günnewig Uebachs”而不是“Günnewig Uebachs”（以空格作为第一个字符）
Nice extra -> no need for extra JAR files in the lib folder so you can keep your application light weight.
不错的额外 -> lib 文件夹中不需要额外的 JAR 文件，因此您可以保持应用程序的轻量级。
回答by Maxim Sidorov
Also you can use java.util.ArrayDeque
你也可以使用 java.util.ArrayDeque
String last = new ArrayDeque<>(Arrays.asList("1-2".split("-"))).getLast();
