Python 如何在函数内部使用while循环？
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How to use while loop inside a function ?
提问by kartikeykant18
I decide to modify the following while loop and use it inside a function so that the loop can take any value instead of 6.
我决定修改以下 while 循环并在函数中使用它，以便循环可以采用任何值而不是 6。
i = 0
numbers = []
while i < 6:
numbers.append(i)
i += 1
I created the following script so that I can use the variable(or more specifically argument ) instead of 6 .
我创建了以下脚本，以便我可以使用变量（或更具体地说是参数）而不是 6 。
def numbers(limit):
i = 0
numbers = []
while i < limit:
numbers.append(i)
i = i + 1
print numbers
user_limit = raw_input("Give me a limit ")
numbers(user_limit)
When I didn't use the raw_input()and simply put the arguments from the script it was working fine but now when I run it(in Microsoft Powershell) a cursor blinks continuously after the question in raw_input()is asked. Then i have to hit CTRL+ Cto abort it. Maybe the function is not getting called after raw_input().
当我不使用raw_input()并简单地将脚本中的参数放入时，它工作正常，但是现在当我运行它时（在 Microsoft Powershell 中），在提出问题后光标会连续闪烁raw_input()。然后我必须点击CTRL+C来中止它。也许函数在 之后没有被调用raw_input()。
Now it is giving a memory error like in the pic.
现在它给出了如图所示的内存错误。
采纳答案by Kobi K
You need to convert user_limitto Int:
您需要转换user_limit为Int：
raw_input()return value is strand the statement is using i which is int
raw_input()返回值是str并且语句使用的是 iint
def numbers(limit):
i = 0
numbers = []
while i < limit:
numbers.append(i)
i = i + 1
print numbers
user_limit = int(raw_input("Give me a limit "))
numbers(user_limit)
Output:
输出：
Give me a limit 8
[0, 1, 2, 3, 4, 5, 6, 7]
