php 表单验证期间带有多个参数的 Codeigniter 中的回调函数
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Callback function in Codeigniter with multiple parameters during form validation
提问by Kamran Ahmed
In Codeigniter:
在代码点火器中：
Here is the callback function that I am using for validation:
这是我用于验证的回调函数：
public function has_match($password, $username){
if (0) {
// user exists
return true;
}
else {
$this->form_validation->set_message('has_match', 'Invalid Username/password entered ' . $password . ' ' . $username);
return false;
}
}
Below are the validation rules:
以下是验证规则：
$this->form_validation->set_rules('username', 'Username', 'required');
$this->form_validation->set_rules('password', 'Password', 'required|callback_has_match[username]');
Can any one please tell me what I am doing wrong here in calling the callback function, as I am unable to get the value of the username field and it keeps showing 'username' (inside the variable $username in callback) instead?
任何人都可以告诉我我在调用回调函数时做错了什么，因为我无法获取用户名字段的值并且它一直显示“用户名”（在回调中的变量 $username 内）？
回答by Petre P?tra?c
Your code is working as expected. You're basically always calling the callback method has_match with the stringusernameas a parameter. I think that you expect that this translates into:
您的代码按预期工作。您基本上总是使用字符串用户名作为参数调用回调方法 has_match 。我认为您希望这会转化为：
callback_has_match[$username]
Therefore, when you access the has_match() method, you would have access to the value of $username. This is however, not the way callback methods work. The parameter that you set in there is a string, which is hardcoded, exactly like you do when you add a rule for min_length[10] - it's not the value of a PHP variable. An easy fix, which I haven't tested but suspect works is to do:
因此，当您访问 has_match() 方法时，您将可以访问$username的值。然而，这不是回调方法的工作方式。您在其中设置的参数是一个硬编码的字符串，与您为 min_length[10] 添加规则时所做的完全一样 - 它不是 PHP 变量的值。一个简单的修复方法，我还没有测试过，但可疑的工作是：
$this->form_validation->set_rules('password', 'Password', 'required|callback_has_match[' . $username . ']');
However the code above is not clean, and seems bad design in my opinion.
然而，上面的代码并不干净，在我看来似乎设计很糟糕。
Now that we've found the problem with the code, I know it's outside the scope of the question, but I would like to point it out - I find it's more of a design issue here. Why do you want to check for the username/password pair inside of a callback to the password field?
现在我们已经找到了代码的问题，我知道它超出了问题的范围，但我想指出它 - 我发现这更像是一个设计问题。为什么要在密码字段的回调中检查用户名/密码对？
Remember, you're validating a form, you shouldn't mix it up with model work. The form doesn't care if the provided username/password combo is correct, it should just look at whether both the fields have been provided correctly, and if so, it should do something about it.
请记住，您正在验证表单，不应将其与模型工作混为一谈。表单并不关心所提供的用户名/密码组合是否正确，它应该只查看两个字段是否都已正确提供，如果是，则应该对其进行处理。
I would adapt your code above to:
我会将您上面的代码调整为：
$this->form_validation->set_rules('username', 'Username', 'required');
$this->form_validation->set_rules('password', 'Password', 'required|callback_has_match[username]');
if ($this->form_validation->run() != FALSE) {
$validLogin = $this->muser->checkLogin($username, $password);
if ($validLogin) {
//Username/password combo exists in DB, save in session or whatever.
} else {
//Username/password combo does not exist in DB, show an error.
}
} else {
//Code for when form fields have not been provided correctly.
}
回答by Muhammad Raheel
Instead of sending parameters with call back you can always get them with post
您可以随时通过 post 获取参数，而不是通过回调发送参数
Here is your call back
这是您的回电
public function has_match(){
if (0) {
// user exists
return true;
}
else {
$password = $this->input->post('password');
$username = $this->input->post('username');
$this->form_validation->set_message('has_match', 'Invalid Username/password entered ' . $password . ' ' . $username);
return false;
}
}
回答by sokhy
// CALLBACKS
// 回调
public function check_user(){
公共函数 check_user(){
$result = FALSE;
$username=$this->input->post('username');
$email=$this->input->post('emailad');
$dbmember=$this->members->get_members();
foreach ( $dbmember as $key){
// condition of username and email
if($username==$key && $email==$key){
if($username == $key->UserName && $email == $key->EmailAddress){
$this->form_validation->set_message('check_user','already existed!
Please check username and email agian.');
return FALSE;
break;
}
return TRUE;
}
}
