C# 在 linq 的 where 方法中使用多个条件
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Using more than one condition in linq's where method
提问by GurdeepS
I have a line of code using where:
我有一行代码使用 where:
codebase.Methods.Where(x => x.Body.Scopes.Count > 5);
How can I insert more than one condition? So I can say x => predicate && y => predicate
?
如何插入多个条件?所以我可以说x => predicate && y => predicate
?
Thanks
谢谢
采纳答案by LukeH
You can roll your separate conditions into a single predicate if you like:
如果您愿意,可以将单独的条件合并为单个谓词:
codebase.Methods.Where(x => (x.Body.Scopes.Count > 5) && (x.Foo == "test"));
Or you can use a separate Where
call for each condition:
或者您可以Where
对每个条件使用单独的调用:
codebase.Methods.Where(x => x.Body.Scopes.Count > 5)
.Where(x => x.Foo == "test");
回答by Jeeva Subburaj
like this..
像这样..
codebase.Methods.Where(x => x.Body.Scopes.Count > 5 && x.Body.Scopes.Count < 10);
回答by TheSoftwareJedi
What would "y" represent?
“y”代表什么?
You can just use a standard && condition. No need for a "y":
您可以只使用标准 && 条件。不需要“y”:
codebase.Methods.Where(x => x.Body.Scopes.Count > 5 && x.Body.SomethingElse < 14);
回答by Rex M
In your example, where does y
come from? The Where
method takes a lambda with a single input parameter, which represents a single instance of the sequence you're operating against.
在你的例子中,y
从哪里来?该Where
方法采用带有单个输入参数的 lambda,该参数表示您正在操作的序列的单个实例。
You can, of course, have multiple conditions against x
:
当然,您可以针对x
以下条件设置多个条件:
Where(x => x.Foo > 5 && x.Bar < 3)
回答by Klaus Byskov Pedersen
I don't get it. What can you not do?
我不明白。你不能做什么?
codebase.Methods.Where(x => x.Head.IsHairy && x.Body != null && x.Body.Scopes.Count > 5);
回答by Amgad Fahmi
no you can't define 2 delegates in the same where but you can build after each other or put both on same condition like this
不,你不能在同一个地方定义 2 个委托,但你可以互相构建或像这样将两者放在相同的条件下
var result = codebase.Methods.Where(x => x.Body.Scopes.Count > 5 && x.Body.Scopes.name == "" );
or
var result = codebase.Methods.Where(x => x.Body.Scopes.Count > 5 )
.where( y=> y.Body.Scopes.name == '' );
or
var result = codebase.Methods.Where(x => x.Body.Scopes.Count > 5 )
.Union( codebase.Methods.Where(y => y.Body.Scopes.name == '' ) );
回答by Majosty D
codebase.Methods.Where(x => x.Body.Scopes.Count > 5).Where(x => x.Body.Scopes.TypeName == "Scopes").Where(x => x.Body.Scopes.Level == LEVEL_HIGH);