Python 如何在 sqlalchemy ORM 查询中使用 NOT IN 子句

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时间:2020-08-19 00:11:24  来源:igfitidea点击:

How to use NOT IN clause in sqlalchemy ORM query

pythonmysqlsqlalchemy

提问by nuttynibbles

how do i convert the following mysql query to sqlalchemy?

我如何将以下 mysql 查询转换为 sqlalchemy?

SELECT * FROM `table_a` ta, `table_b` tb where 1
AND ta.id = tb.id
AND ta.id not in (select id from `table_c`)

so far i have this for sqlalchemy:

到目前为止,我对 sqlalchemy 有这个:

query = session.query(table_a, table_b)
query = query.filter(table_a.id == table_b.id)

回答by Slava Bacherikov

Try this:

尝试这个:

subquery = session.query(table_c.id)
query = query.filter(~table_a.id.in_(subquery))

Note: table_a, table_band table_cshould be mapped classes, not Tableinstances.

注:table_atable_b并且table_c应该被映射类,而不是Table实例。

回答by nuttynibbles

here is the full code:

这是完整的代码:

#join table_a and table_b
query = session.query(table_a, table_b)
query = query.filter(table_a.id == table_b.id)

# create subquery
subquery = session.query(table_c.id)
# select all from table_a not in subquery
query = query.filter(~table_a.id.in_(subquery))

回答by fedorqui 'SO stop harming'

The ORM internals describe the notin_()operator, so you can say:

ORM 内部描述了notin_()操作符,所以你可以说:

query = query.filter(table_a.id.notin_(subquery))
#                               ^^^^^^

From the docs:

从文档:

inherited from the notin_()method of ColumnOperators

implement the NOT INoperator.

This is equivalent to using negation with ColumnOperators.in_(), i.e. ~x.in_(y).

继承自的notin_()方法ColumnOperators

实施NOT IN运算符。

这等效于对ColumnOperators.in_(),即使用否定~x.in_(y)