Java 使用 Jackson 将 Map 转换为 JSON
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Convert Map to JSON using Hymanson
提问by PacificNW_Lover
How can I convert a Map to a valid JSON using Hymanson?
如何使用 Hymanson 将 Map 转换为有效的 JSON？
I am doing it using Google's GSON via a Spring Boot REST Post method...
我正在通过 Spring Boot REST Post 方法使用 Google 的 GSON 来做这件事...
Here's the RESTful Web Service:
这是 RESTful Web 服务：
import java.util.Map;
import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.RestController;
import com.fasterxml.Hymanson.core.JsonFactory;
import com.fasterxml.Hymanson.core.JsonParser;
import com.google.gson.Gson;
@RestController
@RequestMapping("/myservice")
public class ValidationService {
@RequestMapping(value="/validate", method = RequestMethod.POST)
public void validate(@RequestBody Map<String, Object> payload) throws Exception {
Gson gson = new Gson();
String json = gson.toJson(payload);
System.out.println(json);
}
}
So, when I invoke it using this:
所以，当我使用这个调用它时：
curl -H "Accept: application/json" -H "Content-type: application/json" \
-X POST -d '{"name":"value"}' http://localhost:8080/myservice/validate
Receive the following to stdout (this is exactly what I want):
将以下内容接收到标准输出（这正是我想要的）：
{"name":"value"}
Is there a better way to do this using Hymanson instead of Google's Gson and / or am I going about it the wrong way altogether?
有没有更好的方法来使用 Hymanson 而不是 Google 的 Gson 和/或者我是否完全以错误的方式来解决这个问题？
回答by Arpit Aggarwal
You should prefer Object Mapper instead. Here is the link for the same : Object Mapper - Spring MVC way of Obect to JSON
您应该更喜欢 Object Mapper。这是相同的链接：Object Mapper - Spring MVC way of Obect to JSON
回答by Mithun
You can convert Mapto JSONusing Hymanson as follows:
您可以按如下方式转换Map为JSON使用 Hymanson：
Map<String,String> payload = new HashMap<>();
payload.put("key1","value1");
payload.put("key2","value2");
String json = new ObjectMapper().writeValueAsString(payload);
System.out.println(json);
回答by sebster
If you're using Hymanson, better to convert directly to ObjectNode.
如果您使用的是 Hymanson，最好直接转换为 ObjectNode。
//not including SerializationFeatures for brevity
static final ObjectMapper mapper = new ObjectMapper();
//pass it your payload
public static ObjectNode convObjToONode(Object o) {
StringWriter stringify = new StringWriter();
ObjectNode objToONode = null;
try {
mapper.writeValue(stringify, o);
objToONode = (ObjectNode) mapper.readTree(stringify.toString());
} catch (IOException e) {
e.printStackTrace();
}
System.out.println(objToONode);
return objToONode;
}
回答by Uzair
Using Hymanson, you can do it as follows:
使用 Hymanson，您可以按如下方式进行：
ObjectMapper mapper = new ObjectMapper();
String clientFilterJson = "";
try {
clientFilterJson = mapper.writeValueAsString(filterSaveModel);
} catch (IOException e) {
e.printStackTrace();
}
