确保用户名仅包含：AZ、az、.、_、-、0-9（无逗号）PHP
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/12808002/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Make sure username contains only: A-Z, a-z, ., _, -, 0-9 (no comma) PHP
提问by user115422
Possible Duplicate:
regular expression for letters, numbers and - _
可能的重复：
字母、数字和 - _ 的正则表达式
I am creating a signup form in PHP and need to ensure that user's usernames don't contain unwanted characters. Is there anyway I can create a function that returns true for A-Z a-z 0-9 - . _.
我正在用 PHP 创建一个注册表单，需要确保用户的用户名不包含不需要的字符。无论如何我可以创建一个为A-Z a-z 0-9 - . _.
Also I do not want the user's emails to be from yahoo as for some reason they reject the confirmation emails sent. Along with __FILTER_VALIDATE_EMAIL__what would I need to add?
此外，我不希望用户的电子邮件来自雅虎，因为出于某种原因，他们拒绝了发送的确认电子邮件。伴随着__FILTER_VALIDATE_EMAIL__什么，我需要补充的吗？
PS: is there anything wrong with the characters I have mentioned above? I have noted that gmail doesn't allow -_only . and YouTube only alpha-numeric characters.
PS：我上面提到的人物有什么问题吗？我注意到 gmail-_只允许. 和 YouTube 仅限字母数字字符。
回答by Sam
Edited to use \w instead of a-zA-Z0-9_
编辑为使用 \w 而不是 a-zA-Z0-9_
if(preg_match("/[^\w-.]/", $user)){
// invalid character
}
if(!filter_var($email, FILTER_VALIDATE_EMAIL) || strstr($email,'@yahoo.com')) {
// either invalid email, or it contains in @yahoo.com
}
回答by otporan
<?php
// The validator class
class Validator
{
public function isValidUsername($username)
{
if(preg_match('/^[a-zA-Z0-9_\-\.]+$/', $username)) {
return true;
}
return false;
}
public function isYahooMail($mail) {
if(preg_match('/^[a-zA-Z0-9_\-\.][email protected]$/', $mail)) {
return true;
}
return false;
}
}
// The way to use this class
$username = "otporan_123";
$email = "[email protected]";
$badUsername = "otporan*bad";
$yahooEmail = "[email protected]";
$validator = new Validator();
var_export($validator->isValidUsername($username));
echo "<br />";
var_export($validator->isValidUsername($badUsername));
echo "<br />";
var_export($validator->isYahooMail($email));
echo "<br />";
var_export($validator->isYahooMail($yahooEmail));
echo "<br />";
?>
This code would return: true false false true
此代码将返回： true false false true
This is a class, but you can see whats going on in methods and write your own functions if you like procedural code :)
这是一个类，但是如果您喜欢过程代码，您可以查看方法中发生的事情并编写自己的函数:)
Hope this helps!
希望这可以帮助！
回答by circusdei
if(preg_match("/[^-A-Za-z0-9._ ]/", $userName)){
// there are one or more of the forbidden characters (the set of which is unknown)
}
回答by chmeliuk
if (!preg_match('/\w\-/', $username) {
//throw error
}
