在 Node.js 中组织路由
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Organize routes in Node.js
提问by NilColor
I start to look at Node.js. Also I'm using Express.
And I have a question - how can I organize web application routes? All examples just put all this app.get/post/put()handlers in app.js and it works just fine. This is good but if I have something more than a simple HW Blog? Is it possible to do something like this:
我开始研究 Node.js。我也在使用 Express。我有一个问题 - 如何组织 Web 应用程序路由？所有示例都将所有这些app.get/post/put()处理程序放在 app.js 中，它工作得很好。这很好，但如果我有比简单的硬件博客更多的东西？是否有可能做这样的事情：
var app = express.createServer();
app.get( '/module-a/*', require('./module-a').urls );
app.get( '/module-b/*', require('./module-b').urls );
and
和
// file: module-a.js
urls.get('/:id', function(req, res){...}); // <- assuming this is handler for /module-a/1
In other words - I'd like something like Django's URLConf but in Node.js.
换句话说 - 我想要像 Django 的 URLConf 但在 Node.js 中的东西。
采纳答案by TK-421
Check out the examples here:
在此处查看示例：
https://github.com/visionmedia/express/tree/master/examples
https://github.com/visionmedia/express/tree/master/examples
'mvc' and 'route-separation' may be helpful.
'mvc' 和 'route-separation' 可能会有所帮助。
回答by Vegar
I found a short example in ′Smashing Node.js: JavaScript Everywhere′ that I really liked.
我在 ' Smashing Node.js: JavaScript Everywhere' 中找到了一个我非常喜欢的简短示例。
By defining module-aand module-bas its own express applications, you can mount them into the main application as you like by using connects app.use( ):
通过定义module-a并module-b作为自己的快速应用程序，您可以使用connects app.use()将它们挂载到主应用程序中：
module-a.js
模块-a.js
module.exports = function(){
var express = require('express');
var app = express();
app.get('/:id', function(req, res){...});
return app;
}();
module-b.js
模块-b.js
module.exports = function(){
var express = require('express');
var app = express();
app.get('/:id', function(req, res){...});
return app;
}();
app.js
应用程序.js
var express = require('express'),
app = express();
app.configure(..);
app.get('/', ....)
app.use('/module-a', require('./module-a'));
app.use('/where/ever', require('./module-b'));
app.listen(3000);
This would give you the routes
这会给你的路线
localhost:3000/
localhost:3000/module-a/:id
localhost:3000/where/ever/:id
回答by Koen.
There also is a screencast of @tjholowaychuk (creator of express) where he uses the method @Vegar described.
还有一个@tjholowaychuk（express 的创建者）的截屏视频，他使用了@Vegar 描述的方法。
Available on Vimeo: Modular web applications with Node.js and Express
Vimeo 上可用：带有 Node.js 和 Express 的模块化 Web 应用程序
回答by hadaytullah
One more alternative;
另一种选择；
App.js
应用程序.js
var express = require('express')
, routes = require('./routes')
, user = require('./routes/user')
, http = require('http')
, path = require('path');
var app = express();
// all environments
app.set('port', process.env.PORT || 3000);
app.get('/', routes.index);
app.get('/users/:id', user.getUser);
http.createServer(app).listen(app.get('port'), function(){
console.log('Express server listening on port ' + app.get('port'));
});
index.js
索引.js
exports.index = function(req, res){
res.render('index', { title: 'Express' });
};
user.js
用户.js
exports.getUser = function(req, res){
//your code to get user
};
回答by Alexander Bykhov
Check out the articleabout the express-routescannode module. This module helps to organize maintainable routing for express application. You can try it. This is the best solution for me.
退房文章有关的明示，routescan节点模块。该模块有助于为快速应用程序组织可维护的路由。你可以试试看。这对我来说是最好的解决方案。
回答by Minh Hoang
There are several ways to do:
有几种方法可以做到：
1:
1：
module1(app.route('/route1'));
module2(app.route('/route2'));
In the modules you can just implement 1 function to handle the http methods:
在模块中，您只需实现 1 个函数来处理 http 方法：
module.exports = function(route) {
route
.get(function(req, res, next) {
...
}).
.post(function(req, res, next) {
...
});
}
2: if you want to handle the route by a sub-app instead of a module/middleware :
2：如果您想通过子应用程序而不是模块/中间件来处理路由：
var m1 = require(module1.js);
var m2 = require(module2.js);
app.use('/route1', r1);
app.use('/route2', r2);
