Java 必需：找到的变量：值
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Required: Variable Found: Value
提问by Alex
public static int biggestArrayGap(int []a, int n)
{
int biggestGap = Math.abs(a[1]-a[0]);
for (int i=1; i<n-1; i++)
{
if (Math.abs(a[i]-a[i-1]) > biggestGap)
Math.abs(a[i]-a[i-1]) = biggestGap;
}
return biggestGap;
}
For some reason, the second line in the if statement is returning as unexpected type– required: variable found: value. I tried == and that obviously didn't work. Any insight?
出于某种原因，if 语句中的第二行以意外类型返回 - 必需的：找到的变量：值。我试过 == 显然没有用。任何见解？
采纳答案by Sirko
You switched the operands in your assign statement.
您在分配语句中切换了操作数。
Switch this
切换这个
Math.abs(a[i]-a[i-1]) = biggestGap;
to this
对此
biggestGap = Math.abs(a[i]-a[i-1]);
Math.abs(a[i]-a[i-1])returns just an int value (no variable reference or similar). So your trying to assign a new value to a value. Which is not possible. You can just assign a new value to a variable.
Math.abs(a[i]-a[i-1])只返回一个 int 值（没有变量引用或类似的）。所以你试图为一个值分配一个新值。这是不可能的。您可以只为变量分配一个新值。
回答by Keppil
You have reversed your assign statement. Change it to
你已经撤销了你的赋值语句。将其更改为
biggestGap = Math.abs(a[i]-a[i-1]);
回答by Theodoros Chatzigiannakis
You are trying to assign the value of biggestGapto the number returned by Math.abs(). Naturally, you can't, because that value depends on what Math.abs()contains and how it handles its arguments.
您正在尝试将 的值分配给biggestGap返回的数字Math.abs()。当然，您不能，因为该值取决于Math.abs()包含的内容以及它如何处理其参数。
Perhaps you meant the opposite:
也许你的意思相反：
biggestGap = Math.abs(a[i]-a[i-1]);
