Android 文件包含路径分隔符。
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File contains a path separator.
提问by Jason O.
When I try to check the existence of a particular file, I get java.lang.illegalArgumentException: File contains a path separator
当我尝试检查特定文件是否存在时，我得到 java.lang.illegalArgumentException: File contains a path separator
What is the right way to do this using getFileStreamPath(..)?
使用 getFileStreamPath(..) 执行此操作的正确方法是什么？
File file = getActivity().getFileStreamPath("mnt/sdcard/photo/1342147146535.jpg");
if(file.exists()){
Toast.makeText(getActivity(), "File exists in /mnt", Toast.LENGTH_SHORT);
}
I also tried the following to replace the first line of the above codes. None of these worked.
我还尝试了以下替换上述代码的第一行。这些都没有奏效。
File file = getActivity().getFileStreamPath("file:///mnt/sdcard/photo/aviary_1342147146535.jpg");
File file = getActivity().getFileStreamPath("/mnt/sdcard/photo/1342147146535.jpg");
// File file = getActivity().getFileStreamPath("mnt/sdcard/photo/1342147146535.jpg");
// File file = getActivity().getFileStreamPath("file:///mnt/sdcard/photo/1342147146535.jpg");
if(file.exists()){
Toast.makeText(getActivity(), "File exists in /mnt", Toast.LENGTH_SHORT);}
else {
Toast.makeText(getActivity(), "File NOT exists in /mnt", Toast.LENGTH_SHORT);}
采纳答案by Dipak Keshariya
回答by user1154390
I had same problem when I was trying with method getFileStreamPath. I think it takes file as parameter not whole path that why it through exception. Isolved with following method.
我在尝试使用 getFileStreamPath 方法时遇到了同样的问题。我认为它将文件作为参数而不是整个路径，这就是为什么它通过异常。用以下方法解决。
public static Boolean fileExist(Activity activity , String filePath) {
String finalPath = activity.getFilesDir().toString() + File.separator + filePath;
File file = new File(finalPath);
return file.exists();
}
