Javascript jQuery - 从字符串数组中删除重复项
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jQuery - remove duplicates from an array of strings
提问by void
Possible Duplicate:
Easiest way to find duplicate values in a JavaScript array
jQuery.unique on an array of strings
I'm trying to get a neighbor list by breadth-first search (to be specific: the indexes of same color neighbor balls in Block'd)
my function getWholeList(ballid)return an array like
我正在尝试通过广度优先搜索来获取邻居列表（具体来说：Block'd中相同颜色邻居球的索引）我function getWholeList(ballid)返回一个数组
thelist=["ball_1","ball_13","ball_23","ball_1"]
and of course there are duplicates.
当然也有重复。
I tried to remove them with jQuery.unique(); but it does not work with strings I guess, so is there any way for this(making the array unique) ?
我试图用 jQuery.unique(); 删除它们。但我猜它不适用于字符串，所以有什么方法可以做到这一点（使数组唯一）？
Thanks for any help..
谢谢你的帮助..
回答by Guffa
The jQuery uniquemethodonly works on an array of DOM elements.
jQueryunique方法仅适用于 DOM 元素数组。
You can easily make your own uniqe function using the eachand inArraymethods:
您可以使用each和inArray方法轻松创建自己的 uniqe 函数：
function unique(list) {
var result = [];
$.each(list, function(i, e) {
if ($.inArray(e, result) == -1) result.push(e);
});
return result;
}
回答by KooiInc
As a non jquery solution you could use the Arrays filtermethod like this:
作为非 jquery 解决方案，您可以filter像这样使用 Arrays方法：
var thelist=["ball_1","ball_13","ball_23","ball_1"],
thelistunique = thelist.filter(
function(a){if (!this[a]) {this[a] = 1; return a;}},
{}
);
//=> thelistunique = ["ball_1", "ball_13", "ball_23"]
As extension to Array.prototype(using a shortened filtercallback)
作为扩展Array.prototype（使用缩短的filter回调）
Array.prototype.uniq = function(){
return this.filter(
function(a){return !this[a] ? this[a] = true : false;}, {}
);
}
thelistUnique = thelist.uniq(); //=> ["ball_1", "ball_13", "ball_23"]
[Edit 2017] An ES6 take on this could be:
[ Edit 2017] ES6 对此的看法可能是：
Array.from(["ball_1","ball_13","ball_23","ball_1"]
.reduce( (a, b) => a.set(b, b) , new Map()))
.map( v => v[1] );
回答by white
Try this one - Array.unique()
试试这个 - Array.unique()
Array.prototype.unique =
function() {
var a = [];
var l = this.length;
for(var i=0; i<l; i++) {
for(var j=i+1; j<l; j++) {
// If this[i] is found later in the array
if (this[i] === this[j])
j = ++i;
}
a.push(this[i]);
}
return a;
};
thelist=["ball_1","ball_13","ball_23","ball_1"]
thelist=thelist.unique()
回答by obe6
jQuery.unique() only works for array of DOM elements. Take a look at this (enhanced version of unique) :
jQuery.unique() 仅适用于 DOM 元素数组。看看这个（unique的增强版）：
回答by Petah
There is a JavaScript port of the PHP array_uniquefunction here: http://phpjs.org/functions/array_unique
这里有 PHParray_unique函数的 JavaScript 端口：http: //phpjs.org/functions/array_unique
function array_unique (inputArr) {
var key = '',
tmp_arr2 = {},
val = '';
var __array_search = function (needle, haystack) {
var fkey = '';
for (fkey in haystack) {
if (haystack.hasOwnProperty(fkey)) {
if ((haystack[fkey] + '') === (needle + '')) {
return fkey;
}
}
}
return false;
};
for (key in inputArr) {
if (inputArr.hasOwnProperty(key)) {
val = inputArr[key];
if (false === __array_search(val, tmp_arr2)) {
tmp_arr2[key] = val;
}
}
}
return tmp_arr2;
}
Or as of later JS:
或者从后来的 JS 开始：
arr.filter((v, p) => arr.indexOf(v) == p)
