无法使用 JavaScript fetch 获取响应状态代码
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can't get response status code with JavaScript fetch
提问by ali mottaghian
I'm trying to create a login form. when I'm testing the service with Postman, I will get a body object with status code and etc.
我正在尝试创建一个登录表单。当我用 Postman 测试服务时，我会得到一个带有状态代码等的 body 对象。
But, with JavaScript fetch, I can't get body object and I just received an error:
但是，使用 JavaScript fetch 时，我无法获取 body 对象，而且我刚刚收到一个错误：
export const login = (username,password) => {
return dispatch=>{
const basicAuth = 'Basic ' + btoa(username + ':' + password);
let myHeaders = new Headers();
myHeaders.append('Authorization', basicAuth);
myHeaders.append('Content-Type', 'application/json');
fetch(`${baseUrl}api/user/login`, {
withCredentials: true,
headers: myHeaders
})
.then(function (response) {
return response.json();
})
.then(function (json) {
dispatch(setLoginInfo(json))
})
.catch(err =>{
console.log(err)
dispatch(loginFailed())
});
}
}
I need to get status code in fetch.
我需要在 fetch 中获取状态代码。
回答by T.J. Crowder
The status code is the statusproperty on the response object. Also, unless you're using JSON with your errorresponses (which some people do, of course), you need to check the status code (or the okflag) before calling json:
状态代码是status响应对象的属性。此外，除非您在错误响应中使用 JSON （当然有些人会这样做），否则您需要在调用之前检查状态代码（或ok标志）json：
fetch(`${baseUrl}api/user/login`, {
withCredentials: true,
headers: myHeaders
})
.then(function(response) {
console.log(response.status); // Will show you the status
if (!response.ok) {
throw new Error("HTTP status " + response.status);
}
return response.json();
})
.then(// ...
Not checking that the request succeeded is such a common mistake I wrote it up on my anemic little blog.
不检查请求是否成功是一个常见的错误，我把它写在我贫血的小博客上。
回答by Panther
The statusis present in the responseobject. You can get it inside your first then block
的status是存在于所述response对象。你可以把它放在你的第一个然后阻止
.then(function (response) {
console.log(response.status);
return response.json();
})
Since you are returning response.json(), the subsequent thenand catchonly gets the result of response.json()which is the body of the response.
由于您正在返回response.json()，因此后续then且catch仅获得response.json()响应主体的结果。
