Java 修复错误：未报告的异常 InterruptedException
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Fixing Error: Unreported Exception InterruptedException
提问by Jonathan Lam
I'm new to Java. I was just searching how to make a Java program wait, and it said to use the Thread.sleep()method. However, when I do this it comes up with an error:
我是 Java 新手。我只是在搜索如何让Java程序等待，它说使用该Thread.sleep()方法。但是，当我这样做时，会出现错误：
error: unreported exception InterruptedException; must be caught or declared to be thrown
错误：未报告的异常 InterruptedException；必须被捕获或声明被抛出
I fixed that by adding throws InterruptedExceptionto the method declaration, and now it works.
我通过添加throws InterruptedException到方法声明来解决这个问题，现在它可以工作了。
However, when calling the method, I got the error again. People say to use a throw and catch block, but I'm not sure how to do that yet. Could somebody help me here?
但是，在调用该方法时，我再次收到错误消息。人们说要使用 throw 和 catch 块，但我还不知道该怎么做。有人可以帮我吗？
Anyways, code for Draw.java (with sleep() method):
无论如何，Draw.java 的代码（使用 sleep() 方法）：
package graphics.utilities;
public class Draw {
public static void DS(int[] c)
throws InterruptedException {
\ .. Drawing Algorithms
Thread.sleep(2000);
\ .. More Drawing Algorithms
}
}
And in Square.java (calling DS()):
在 Square.java 中（调用 DS()）：
package graphics.shapes;
import graphics.utilities.*;
public class Square implements Graphics {
int x1,y1,s;
public Square(int x1,int y1,int s) {
this.x1 = x1;
this.y1 = y1;
this.s = s;
}
public void GC() {
System.out.printf("Square Coordinates:%n Start Point:%n x: %d%n y: %d%n Height/Width: %d%n%n" , this.x1,this.y1,this.s);
}
public void D() {
int x2 = x1 + s;
int y2 = y1;
int x3 = x1 + s;
int y3 = y1 + s;
int x4 = x1;
int y4 = y1 + s;
int[] c = {x1,y1,x2,y2,x3,y3,x4,y4};
Draw.DS(c);
}
}
Thanks.
谢谢。
采纳答案by Developer Marius ?il?nas
Provided example demonstrates how to do exception pass up the call chain (up the method call chain). For this your method declaration contains a throws InterruptedException.
提供的示例演示了如何在调用链上（方法调用链上）进行异常传递。为此，您的方法声明包含一个 throws InterruptedException。
Alternative approach is to handle exception in the method it occurred: in your case add
另一种方法是在它发生的方法中处理异常：在你的情况下添加
try
{
Thread.sleep(2000);
}
catch(InterruptedException e)
{
// this part is executed when an exception (in this example InterruptedException) occurs
}
After you added try {} catch() {}block, remove "throws InterruptedException"from the method DS.
添加try {} catch() {}块后，从方法 DS 中删除“throws InterruptedException”。
You can wrap other lines with try {} catch() {}block as required. Read about Java exceptions.
您可以try {} catch() {}根据需要用块包裹其他行。阅读有关Java 异常的信息。
回答by JerryIndia
Simple thread program which illustrates the sleep function comes with JavaThread
JavaThread自带的简单线程程序，说明睡眠功能
class sub implements Runnable{
public void run()
{
System.out.println("thread are started running...");
try
{
Thread.sleep(1000);
}
catch(Exception e)
{
System.out.println(e);
}
System.out.println("running properly.....");
}
public static void main(String[] args)
{
sub r1=new sub();
Thread t1=new Thread(r1);
// with the help of start
t1.start(); } }
