bash zgrep 目录中的多个 gz 文件
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zgrep multiple gz files in directory
提问by Mithrand1r
I have problem executing zgrepcommand for looking for wordin the directory where I have almost 1000 *.gzfiles.
我在执行zgrep命令以word在我有近 1000 个*.gz文件的目录中查找时遇到问题。
I am trying with:
我正在尝试：
find /var/www/page/logs/ -name "*.gz" -exec zgrep '/index.php' {} \;
result is:
结果是：
GET : '/index.php'
GET : '/index.php'
GET : '/index.php'
And it works.I get list of occurance of index.phpwith no file name where it was found. It is kind of useless for me unless i knew in which files (filename) it appears.
它有效。我得到index.php了没有文件名的出现列表。除非我知道它出现在哪个文件（文件名）中，否则它对我来说没什么用。
How can i fix it?
我该如何解决？
回答by devnull
You could supply the -Hoption to list the filename:
您可以提供-H列出文件名的选项：
find /var/www/page/logs/ -name "*.gz" -exec zgrep -H '/index.php' {} \;
If you wanted only the list of matching files, use -l:
如果您只想要匹配文件的列表，请使用-l：
find /var/www/page/logs/ -name "*.gz" -exec zgrep -l '/index.php' {} \;
回答by Mark Setchell
Make grep search in two files, then it will tell you which one it found it in:
在两个文件中进行 grep 搜索，然后它会告诉你它在哪个文件中找到的：
find /var/www/page/logs/ -name "*.gz" -exec zgrep '/index.php' {} /dev/null \;
And it won't take long to search in /dev/null.
在 /dev/null 中搜索不会花费很长时间。
Here is an example without /dev/null:
这是一个没有 /dev/null 的例子：
zgrep chr your.gz
>chrMCHU - Calmodulin - Human, rabbit, bovine, rat, and chicken
>chrgi|5524211|gb|AAD44166.1| cytochrome b [Elephas maximus maximus]
and with /dev/null
和 /dev/null
zgrep chr your.gz /dev/null
your.gz:>chrMCHU - Calmodulin - Human, rabbit, bovine, rat, and chicken
your.gz:>chrgi|5524211|gb|AAD44166.1| cytochrome b [Elephas maximus maximus]
